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ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A Gaussian model with a positive inference gap and a collapsed latent

Example

Assume AC and use Lebesgue measure for the latent densities. In the first model, a scalar latent variable Z has prior N(0,4), and conditional on Z=z the observation is X=(Y1,Y2) with Y1,Y2 IID N(z,1). At the observed value x=(2,4), the evidence is finite and positive and the posterior is N(8/3,4/9). Restrict the encoder family to qm(z∣x)=N(m,4/9) for m∈[−1,1] and choose m=0. This encoder is admissible and its reverse-KL gap, with DKL(q∥π):=∫q(z)log⁡(q(z)/π(z)) dz, is DKL(q0(⋅∣x)∥π(⋅∣x))=8>0, so its ELBO is exactly 8 below the log evidence.

In a second model, let Z∼N(0,1) and use the standard normal density h(x)=(2π)−1/2e−x2/2 for p(x∣z)=h(x), independent of z. For every observation x∈R, the evidence is 0<h(x)<∞ and the posterior equals the prior. Choose the constant encoder q(z∣x)=N(0,1) for every x. Its reverse-KL gap is zero and its ELBO equals the log evidence on every fibre. Thus q(z∣x)=pθ(z∣x)=p(z) for all x, a posterior-collapse configuration in which the decoder ignores the latent variable; this is one model configuration, not a claim that VAE training always collapses.

Facts & Assumptions

Given: AC; the two stated latent-variable models and observations; the restricted encoder family in the first model; and the definitions of evidence, posterior, admissibility and ELBO.

[A1]

The Axiom of Choice: every family of nonempty sets has a choice function; AC is used by the Gaussian density suppliers and the library KL branch.

[F1]

Variational autoencoder model, encoder, and ELBO: for positive finite evidence, π=γ/Z; an encoder is admissible when it is a probability density supported where π is positive with the stated absolute log-integrability; its ELBO is the integral of log⁡γ−log⁡q under q.

[F2]

Known-variance Normal-Normal conjugate update: with prior N(μ0,τ02), positive known variance σ2, and n≥1 IID observations from N(μ,σ2), the evidence is finite and positive and the posterior has variance (τ0−2+nσ−2)−1 and mean equal to that variance times μ0/τ02+nyˉ/σ2.

[F3]

Standard normal and normal laws and A positive-variance normal law has its location-scale density: N(0,1) is a probability law with density e−z2/2/2π, and for σ>0, N(m,σ2) has density (2πσ2)−1/2exp⁡(−(z−m)2/(2σ2)).

[F4]

Location-scale normal laws have their stated mean and variance: a variable with law N(m,σ2) has mean m and finite variance σ2.

[F5]

Kullback–Leibler divergence: for probability measures with densities q and π relative to one reference measure and q μ≪π μ, the reverse divergence is ∫qlog⁡(q/π) dμ.

[F6]

The VAE evidence equals the ELBO plus reverse KL: for each admissible fixed observation under AC, log evidence equals ELBO plus the library reverse-KL divergence.

Verification

Given: The hypotheses in the Example and Facts & Assumptions.

1.1A1F2givenalgebra

In the first model set μ0=0, τ02=4, σ2=1, n=2, and yˉ=(2+4)/2=3. By [F2], the posterior variance is (1/4+2)−1=4/9 and its mean is (4/9)(0+2⋅3)=8/3; the evidence is finite and positive.

1.2A1F1F3F4F5step 1.1algebra

The chosen q0=N(0,4/9) lies in the family because 0∈[−1,1], while the posterior mean 8/3 is outside that interval. Both Gaussian densities are strictly positive, so q0 is supported where the posterior is positive. Their logarithms are quadratic and q0 has finite second moment by [F4], so the absolute log-integrability required in [F1] holds. Using the common-variance density formula [F3], log⁡ ⁣(q0(z∣x)π(z∣x))=(z−8/3)2−z22(4/9)=−6z+8. Taking q0-expectations and using [F4] gives DKL(q0∥π)=8 by the directional convention [F5].

2.1A1F6step 1.2algebra

Applying [F6] to the first model, the log-evidence minus ELBO is exactly this reverse-KL value 8, which is strictly positive.

3.1A1F1F3F4F6algebra∎

In the second model, write h(x)=(2π)−1/2e−x2/2 and let r be the N(0,1) prior density. For every x∈R, [F3] gives 0<h(x)<∞ and ∫r(z) dz=1, so γ(z;x)=r(z)h(x) has evidence Z(x)=h(x) and posterior π(z∣x)=r(z). The constant encoder q(z∣x)=r(z) has full support and finite second moment by [F4]; its log density and log⁡γ(z;x)=log⁡r(z)+log⁡h(x) are integrable under q by [F1]. Thus its reverse-KL is zero and [F6] gives ELBO equal to log evidence on every fibre. The decoder density is independent of z, so q(z∣x)=pθ(z∣x)=p(z) for all x, which is posterior collapse.

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