Alphabeta Math
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Finite VP noise leaves a terminal-prior mismatch

Example

Assume AC. Fix T>0 and a continuous function β:[0,T]→(0,∞). Let (Ω,F,(Ft)t≥0,P) be a complete filtered probability space with a right-continuous filtration, and let W be an adapted standard one-dimensional Brownian motion such that, for every 0≤s<t, Wt−Ws is independent of Fs and has law N(0,t−s). Put B(t)=∫0tβ(r) dr, X0=0, and

Xt=e−B(t)/2∫0teB(r)/2β(r) dWr,0≤t≤T.

This solves the variance-preserving (VP) stochastic differential equation dXt=−12β(t)Xt dt+β(t) dWt. For t>0, its law Pt has density and score

pt(x)=12πvte−x2/(2vt),st(x)=−xvt,vt=1−e−B(t).

Since β is positive and continuous, 0<B(T)<∞ and 0<vT<1, so PT=N(0,vT)≠N(0,1). The predictor-corrector procedure defined above initializes from the actual terminal law PT; replacing that draw by N(0,1) changes the initial law for this finite schedule. No convergence or solver-error claim follows from this comparison.

Facts & Assumptions

Given: AC, the filtered Brownian motion and schedule β in the Example, and its explicit process X.

[A1]

AC, the usual filtration conditions, and independent Brownian increments relative to the filtration are the hypotheses of the Brownian Itô and deterministic-integral interfaces used below. Continuous Brownian Ito processes The Axiom of Choice

[F1]

A process with pathwise integrable drift and a localized Brownian Itô integral is a continuous Brownian Itô process under the stated filtration conditions. Continuous Brownian Ito processes

[F2]

For a one-dimensional Brownian Itô process and a C1,2 function, Itô's formula adds the drift, diffusion, and half-variance second-derivative terms. One-dimensional Ito formula

[F3]

A deterministic square-integrable Itô integrand has a centered normal integral with variance equal to the integral of its square. Deterministic Ito integrals are Gaussian

[F4]

A scalar normal law is the affine image of the standard normal law, and for positive variance v it has density (2πv)−1/2e−x2/(2v). Standard normal and normal laws A positive-variance normal law has its location-scale density

[F5]

At positive finite differentiable density points, the marginal score is the derivative of the log density. Marginal score function

[F6]

The law of a random element is its probability pushforward. Law or distribution of a random element

[F7]

The predictor-corrector procedure's initial draw has law PT. Predictor-corrector sampling for score SDEs

Verification

1.1A1F1F2givenalgebra

Write Kt=∫0teB(r)/2β(r) dWr, whose deterministic integrand is square-integrable because B and β are continuous on [0,T]. Since B′(t)=β(t), apply [F2] to f(t,x)=e−B(t)/2x and the continuous Itô process Kt. The product rule gives dXt=−12β(t)Xt dt+β(t) dWt and X0=0.

1.2F3F4givenalgebra

By [F3], Kt is centered normal with variance ∫0teB(r)β(r) dr. Differentiating eB(r) gives ddreB(r)=eB(r)β(r), so this variance is eB(t)−1. Multiplication by e−B(t)/2 therefore gives Xt∼N(0,e−B(t)(eB(t)−1))=N(0,vt). For t>0, positivity of β implies vt>0; [F4] supplies its displayed density.

2.1F4F5givenstep 1.2algebra

Differentiating the density in step 1.2 gives ∂xlog⁡pt(x)=−x/vt, so [F5] yields the score for every t>0. At t=0, X0=0 almost surely; its law assigns mass one to {0} and therefore has no Lebesgue density, since every Lebesgue-density measure assigns zero mass to that singleton.

3.1F4F6F7step 1.2step 2.1givenalgebra∎

Continuity of β on the compact interval makes B(T) finite, and strict positivity gives B(T)>0. Hence vT=1−e−B(T) lies strictly between zero and one. For any v>0, the density in [F4] and the substitution x=vz give ∫Rx2e−x2/(2v)2πv dx=v∫Rz2e−z2/22π dz=v. Indeed integration by parts yields ∫z2e−z2/2dz=∫e−z2/2dz over R, because ze−z2/2→0 at both ends, and the normalized standard-normal density integrates to one. Thus EPTX2=vT by step 1.2, whereas EN(0,1)Z2=1. If the laws were equal these finite second moments would be equal, a contradiction. Step 2.1 shows the exact positive-time score is available at T, and [F7] prescribes initialization from PT; replacing it by N(0,1) changes that initial law.

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