Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The unit circle traversed three times has index 3 at every interior point

Example

Let γ(t)=exp⁡(3it) for t∈[0,2π]. Then γ is a closed complex contour with trace the unit circle {∣z∣=1}, and

n(γ,z)=3  for ∣z∣<1,n(γ,z)=0  for ∣z∣>1.

The function λ(t)=3it is a continuous logarithm of γ−0 along γ, its imaginary part θ(t)=3t is a continuous argument running from 0 to 6π, and (θ(2π)−θ(0))/(2π)=3 recovers the index at the origin.

Facts & Assumptions

Given: The contour γ(t)=exp⁡(3it) on [0,2π].

[L1]

For a∈C, r>0 and k∈Z, the contour γk(t)=a+rexp⁡(ikt) on [0,2π] is a closed complex contour with n(γk,z)=k for ∣z−a∣<r and n(γk,z)=0 for ∣z−a∣>r; for k≠0 its trace is {z:∣z−a∣=r} (A circle traversed k times has winding number k inside and 0 outside).

[L2]

For a closed complex contour γ, a point p off its trace and a continuous argument θ of γ−p along γ, n(γ,p)=(θ(b)−θ(a))/(2π) (The winding number is the increment of a continuous argument divided by 2π).

[L3]

n(γ,p)=(2πi)−1∫γdz/(z−p) (The winding number of a closed contour about a point off its trace).

[L4]

A continuous logarithm of γ−p along γ is a continuous λ with exp⁡(λ(t))=γ(t)−p for every t, and its continuous argument is Im⁡λ (Continuous logarithms and continuous arguments along a contour).

Verification

technique · direct
1.1givenL1L3

Apply [L1] with a=0, r=1 and k=3: the contour is γ, it is a closed complex contour with trace {∣z∣=1}, and n(γ,z)=3 for ∣z∣<1 while n(γ,z)=0 for ∣z∣>1.

1.2givenL4L5

The map λ(t)=3it is continuous on [0,2π] and satisfies exp⁡(λ(t))=exp⁡(3it)=γ(t)−0, so it is a continuous logarithm of γ−0 along γ in the sense of [L4], with continuous argument θ(t)=Im⁡(3it)=3t by [L5].

2.1step 1.1step 1.2L2∎

The argument increment is θ(2π)−θ(0)=6π−0=6π, so [L2] gives n(γ,0)=6π/(2π)=3, the same value step 1.1 assigns at the interior point 0.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources