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DefinitionDefinition: Literature-sourcedProof: Not applicablejudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
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Continuous logarithms and continuous arguments along a contour

Definition

Let γ:[a,b]→C be a complex contour (Rectifiable complex contours, reversal, concatenation, closedness, and orientation) with trace γ∗, and let p∈C with p∉γ∗.

A continuous logarithm of γ−p along γ is a continuous function λ:[a,b]→C with

exp⁡(λ(t))=γ(t)−pfor every t∈[a,b],

the exponential being that of The complex exponential by its power series. The associated continuous argument of γ−p along γ is θ:=Im⁡λ:[a,b]→R (Real and imaginary parts, complex conjugation, and modulus).

Let V⊆C be open with p∉V. A holomorphic logarithm branch of z−p on V is a holomorphic function L:V→C (Complex differentiability at a point, the complex derivative, holomorphic functions, and entire functions) with

exp⁡(L(z))=z−pfor every z∈V.

Remarks

These are two different objects and only the first is unconditional. A continuous logarithm along γ is a function of the parameter t; it exists for every complex contour missing p, and prescribing the single value λ(a) among the complex numbers whose exponential is γ(a)−p determines it, both by Every contour missing a point admits a continuous logarithm, unique up to a constant in 2πiZ ↗. A holomorphic logarithm branch is a function on a plane set, and for a general open V missing p there need be none.

Along a contour, whose parameter interval is connected, two continuous logarithms differ by one additive constant in 2πiZ. On a general open set V, two holomorphic branches differ by a locally constant 2πiZ-valued function, hence by one such constant on each connected component; a single global constant is forced only when V is connected. This follows from ker⁡(exp⁡)=2πiZ (ker⁡(exp⁡)=2πiZ, and exp⁡z=exp⁡w exactly when z−w∈2πiZ). For p=0 and V the slit plane, Complex logarithms, the principal logarithm, and principal and multivalued complex powers names the principal logarithm; its holomorphy on that domain is proved later on this page.

A continuous argument θ carries no normalisation of its own: adding 2πk to θ for a fixed integer k replaces λ by λ+2πik, which is again a continuous logarithm. What is unambiguous is the increment θ(b)−θ(a), since the two choices differ by the same constant at both endpoints.

Depends on

Used by

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Sources