Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedaudited 2026-09-22
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B and C are always isomorphic

Statement

False for n3: Bn and Cn are dual to one another but are not isomorphic root systems; only n2 gives an isomorphism.

Facts & Assumptions

Given: The standard coordinate models Bn={±εi,±εi±εj:i<j} and Cn={±2εi,±εi±εj:i<j} in Rn.

[L1]

These are the root systems of types Bn and Cn, with the squared lengths 1 and 2 in Bn and 2 and 4 in Cn (Existence of each classified root system, Root systems of the classical complex Lie algebras).

[L2]

An isomorphism of root systems preserves all Cartan integers, hence preserves angles and the ratios of lengths; in an irreducible system it therefore maps roots of maximal length to roots of maximal length and roots of minimal length to roots of minimal length (Rank and isomorphism of root systems, Rank-two root-system classification).

[L3]

B2C2, while for n3 the types are distinct in the classification list (Duality exchanges B and C, Classification of irreducible root systems).

Refutation

technique · counterexample
1.1

In Bn the roots of squared length 2 are the ±εi±εj with i<j, of which there are 2n(n1), and the roots of squared length 1 are the ±εi, of which there are 2n. In Cn the roles are exchanged: the roots of squared length 4 are the ±2εi, of which there are 2n, and the roots of squared length 2 are the ±εi±εj, of which there are 2n(n1).

L1algebra
2.1

An isomorphism BnCn would preserve the length classes by [L2], so it would carry the 2n(n1) long roots of Bn bijectively onto the 2n long roots of Cn and the 2n short roots of Bn onto the 2n(n1) short roots of Cn; for n3 these cardinalities differ, since 2n(n1)>2n. Hence Bn≇Cn for n3. For n=1, the coordinate models in [L1] are B1={±ε1} and C1={±2ε1}, and the linear map x2x carries one onto the other and preserves their sole Cartan integer 2. For n=2 the systems are isomorphic by [L3]. Therefore the isomorphism holds exactly for n2.

L1L2L3step 1.1algebra

Depends on

Used by

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Dependency tree · two levels

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Sources