Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-09-05
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FALSE: effaceability means every positive value is zero

Statement

Assume the Axiom of Dependent Choice.

False. If a delta functor is effaceable in positive degrees, then all of its positive-degree values are zero.

Facts & Assumptions

Given: The right exact functor F=(−)⊗ZZ/n on abelian groups, where n>1 is an integer, together with supplied projective resolution data on all abelian groups.

[L2]

Positive left derived functors of a right exact functor on a category with enough projectives are effaceable (Positive left derived functors are effaceable by projectives).

[L3]

Replacing supplied projective resolution data gives naturally isomorphic left derived functors (Two supplied projective resolution data define naturally isomorphic left derived functors).

Refutation

technique · direct
1.1L1L2given

Every abelian group is a quotient of a free abelian group, so Ab has enough projectives. Hence [L2] makes the positive left derived functors of F effaceable in the sense of [L1].

1.2L3givenalgebra

Let Q be supplied projective resolution data obtained from the given datum by using 0→Z→nZ→Z/n→0 at the object Z/n. Applying F to this resolution gives a deleted complex whose differential n:Z/n→Z/n is zero. Therefore L1QF(Z/n)≅ker⁡(Z/n→0Z/n)≅Z/n≠0. By [L3], L1PF(Z/n)≅L1QF(Z/n) for the original supplied datum P, so its first derived value is nonzero as well.

2.1step 1.1step 1.2∎

Thus this homological delta functor is effaceable in positive degrees but has a nonzero positive-degree value, refuting the statement.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources