Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-30
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A continuous partition of unity need not be smooth

Statement

False claim: every continuous partition of unity on a smooth manifold is smooth.

Facts & Assumptions

Given: The cover U=(,1) and V=(1,) of R.

[F1]

A partition of unity subordinate to an open cover consists of nonnegative functions summing to 1 with supports in the assigned open sets (Smooth partitions of unity subordinate to an open cover).

[A1]

Define ϕ(x):=0 for x1, ϕ(x):=(x+1)/2 for 1x1, ϕ(x):=1 for x1, and ψ:=1ϕ.

Refutation

technique · direct
1.1

The functions from [A1] are continuous, nonnegative, and satisfy ϕ+ψ=1; also supp(ϕ)=[1,)V and supp(ψ)=(,1]U, so they form a continuous subordinate partition in the sense of [F1].

A1F1
1.2

The function ϕ has a corner at 1 and at 1, so it is not smooth.

A1
2.1

Hence a continuous partition of unity need not be smooth.

step 1.1step 1.2

Depends on

Used by

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Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources