How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
FALSE: Every endomorphism has a commuting diagonal-plus-nilpotent decomposition over its base field
Statement
False claim. Every endomorphism over its base field can be written with diagonalisable, nilpotent, and .
Facts & Assumptions
Given: The real quarter-turn .
A commuting family whose characteristic polynomials split is simultaneously triangularisable (A commuting split family is simultaneously triangularisable).
A diagonalisable endomorphism has a basis of eigenvectors (A diagonalisable endomorphism is one admitting a basis of eigenvectors, equivalently a diagonal matrix representation).
A nilpotent endomorphism has characteristic polynomial (Characterisations of a nilpotent endomorphism).
An endomorphism is triangularisable exactly when its characteristic polynomial splits ( is triangularisable iff its minimal polynomial splits iff its characteristic polynomial splits).
Refutation
Suppose as claimed. By [L2], splits, while [L3] makes split; commutation and [L1] give one real basis in which both and are upper triangular.
Their sum is upper triangular in that basis, so [L4] would make split over .
But direct computation gives , which has no real root. This contradiction refutes the claimed decomposition over the base field.
Depends on
- A commuting split family is simultaneously triangularisable
- A diagonalisable endomorphism is one admitting a basis of eigenvectors, equivalently a diagonal matrix representation
- Nilpotent endomorphisms and their nilpotency index
- Characterisations of a nilpotent endomorphism
- $T$ is triangularisable iff its minimal polynomial splits iff its characteristic polynomial splits
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 68 results over 20 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- S. Axler, Linear Algebra Done Right, 4th ed., Result 5.43 (standard reference, not scraped)