Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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FALSE: Every endomorphism has a commuting diagonal-plus-nilpotent decomposition over its base field

Statement

False claim. Every endomorphism T over its base field can be written T=D+N with D diagonalisable, N nilpotent, and DN=ND.

Facts & Assumptions

Given: The real quarter-turn R=(0110).

[L1]

A commuting family whose characteristic polynomials split is simultaneously triangularisable (A commuting split family is simultaneously triangularisable).

[L3]

A nilpotent endomorphism has characteristic polynomial xn (Characterisations of a nilpotent endomorphism).

[L4]

An endomorphism is triangularisable exactly when its characteristic polynomial splits (T is triangularisable iff its minimal polynomial splits iff its characteristic polynomial splits).

Refutation

technique · counterexample
1.1

Suppose R=D+N as claimed. By [L2], χD splits, while [L3] makes χN=x2 split; commutation and [L1] give one real basis in which both D and N are upper triangular.

assume-contraL1L2L3
2.1

Their sum R is upper triangular in that basis, so [L4] would make χR split over R.

step 1.1L4algebra
3.1

But direct computation gives χR=x2+1, which has no real root. This contradiction refutes the claimed decomposition over the base field.

step 2.1discharge-contradictionalgebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 68 results over 20 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources