How statement and proof provenance work
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FALSE: every Hausdorff compactification has the Stone–Čech extension property
Statement
Every Hausdorff compactification has the Stone–Čech extension property.
Facts & Assumptions
Given: The discrete naturals, their one-point compactification , and the parity map .
The one-point compactification of a locally compact Hausdorff noncompact space is a compact Hausdorff space in which the original space is dense ( is compact and contains as an open subspace; is dense in exactly when is not compact; and is Hausdorff exactly when is locally compact and Hausdorff).
Refutation
Discrete is locally compact, Hausdorff, and noncompact, so [L1] makes a Hausdorff compactification.
Suppose it had the Stone–Čech property. Its parity map would then extend continuously to .
The same cofinite-neighbourhood argument as follows directly from The one-point (Alexandroff) compactification , whose open sets are the open sets of together with the complements in of the closed compact subsets of : continuity at would make eventually lie in an interval of radius , while arbitrarily large even and odd naturals have values and . This is impossible.
Therefore this Hausdorff compactification is not Stone–Čech, refuting the displayed statement.
Depends on
- A Hausdorff compactification as a dense embedding into a compact Hausdorff space
- The Stone–Čech compactification by its compact-Hausdorff extension property
- The one-point (Alexandroff) compactification $X^{*} = X \cup \{\infty\}$, whose open sets are the open sets of $X$ together with the complements in $X^{*}$ of the closed compact subsets of $X$
- $X^{*}$ is compact and contains $X$ as an open subspace; $X$ is dense in $X^{*}$ exactly when $X$ is not compact; and $X^{*}$ is Hausdorff exactly when $X$ is locally compact and Hausdorff
- The natural numbers $\mathbb{N}$ (von Neumann)
Used by
Nothing in the library uses this result yet.
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Sources
- E. Moorhouse, The Stone–Čech Compactification (standard reference, not scraped)