Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-07-31
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FALSE: homotopy-equivalent spaces must be homeomorphic

Statement

False claim. If two topological spaces are homotopy equivalent, then they are homeomorphic.

Facts & Assumptions

Given: A one-point space P={p} and the real line R with its usual topology.

[A1]

A map f:X→Y is a homotopy equivalence when it has a continuous g:Y→X with g∘f≃id⁡X and f∘g≃id⁡Y (Homotopy equivalences, homotopy inverses and spaces of the same homotopy type).

[L1]

The real line is a nonempty convex subset of itself, hence is contractible, and its identity is homotopic to the constant map at 0 (Every nonempty convex subset of Rn is contractible, A nonempty space is contractible if and only if its identity map is nullhomotopic).

[L3]

The set R is uncountable, whereas a singleton is finite (R is uncountable (Cantor's nested intervals, 1874)).

Refutation

technique · direct
1.1

Define i:P→R by i(p)=0 and let q:R→P be the unique map. Both are continuous: the preimage of an open set under either map is either empty or the whole domain.

construct
1.2

No bijection P→R exists by [L3], so no homeomorphism exists by [L2].

L2L3
2.1

One has q∘i=id⁡P, while i∘q=c0≃id⁡R by [L1]. Thus i is a homotopy equivalence with homotopy inverse q by [A1].

step 1.1L1A1
3.1

Therefore P and R are homotopy equivalent by step 2.1 but not homeomorphic by step 1.2, refuting the claim.

step 2.1step 1.2∎

Depends on

Used by

Dependency tree · two levels

31 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources