Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-27
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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FALSE: the residue theorem applies to every cycle in the ambient domain

Statement

False claim: if f is meromorphic on an open set Ω and Γ is any cycle in ΩS, then

Γf(z)dz=2πiaSn(Γ,a)Res(f,a).

The missing hypothesis is that Γ be null-homologous in Ω.

Facts & Assumptions

Given: The punctured plane Ω=C{0}, the function f(z)=1/z, and the positively oriented unit circle Γ.

[L1]

The residue theorem requires an admissible cycle, hence in particular null-homology in the ambient open set (Admissible cycles for the residue theorem, The residue theorem for a null-homologous cycle).

Refutation

technique · direct
1.1

In the punctured plane Ω=C{0}, the unit circle is not null-homologous: its winding number about the omitted point 0 is 1, not 0.

given
2.1

The function 1/z is holomorphic on Ω, so its pole set in the ambient domain is empty and the right-hand sum in the false claim is 0. However, the contour integral around the unit circle is 2πi. Thus the displayed equality fails, exactly because the cycle is not null-homologous in Ω.

step 1.1L1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources