Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-27
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FALSE: existence of a Cauchy principal value forces improper convergence

Statement

False claim: if PV⁡ ⁣∫−∞∞f(x) dx exists, then ∫−∞∞f(x) dx exists as an ordinary improper integral.

Facts & Assumptions

Given: The odd rational function f(x)=x/(1+x2).

[L1]

Principal value is defined by symmetric truncation and does not by itself assert separate one-sided convergence (Cauchy principal values at a finite singularity and on the real line, This page keeps Cauchy principal values distinct from genuine improper convergence).

[L2]

Ordinary improper convergence implies principal-value convergence, but the implication is not stated as an equivalence (Separate improper convergence implies convergence of the principal value).

Refutation

technique · direct
1.1L1

Because f is odd, [given, L1] ∫−RRx1+x2 dx=0 for every R>0, so gives PV⁡ ⁣∫−∞∞x1+x2 dx=0.

2.1step 1.1L2algebra

On (0,∞) one has x/(1+x2)∼1/x, so ∫1∞x1+x2 dx=12log⁡(1+x2)∣1∞ diverges to +∞, and by oddness the left tail diverges to −∞. Therefore the ordinary improper integral does not exist.

3.1step 1.1step 2.1∎

So the existence of a principal value does not force ordinary improper convergence.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources