Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
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A sector-area squeeze proves lim sin(x)/x=1 without first calibrating angle measure

Statement

False claim: the sector-area inequalities sinθ<θ<tanθ\sin\theta<\theta<\tan\theta prove limx0sinx/x=1\lim_{x\to0}\sin x/x=1 without any prior calibration of the angle variable θ\theta to arc length, sector area, and π\pi.

Facts & Assumptions

Given: The analytic sine function and the definition π=2γ\pi=2\gamma from the first positive cosine zero.

[L1]

The analytic proof already establishes limx0sinx/x=1\lim_{x\to0}\sin x/x=1 (The limit of sin x divided by x at zero is one).

[L2]

π\pi is defined analytically from cosine, not from geometric sector area (Pi as twice the smallest positive zero of cosine).

Refutation

technique · direct
1.1

The sector inequality uses an angle measured in radians, and its usual derivation identifies that measure through arc length or sector area in the unit circle.

given
1.2

Establishing that identification requires a normalization constant, equivalently the relationship between the geometric full turn and the analytic π\pi of [L2].

L2
2.1

Thus the sector argument cannot be used as a foundation independent of that calibration; it may prove the limit only after importing the relation whose analytic construction it was meant to justify.

step 1.1step 1.2
3.1

The limit itself remains true by [L1], but the claimed independent proof is false.

step 2.1L1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 19 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources