Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-02
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The extension of x^2 sin(1/x) by zero is differentiable but its derivative is discontinuous at zero

Example

Define f(0)=0 and f(x)=x2sin⁡(1/x) for x≠0. Then f is differentiable on R, with f′(0)=0, but f′ is not continuous at 0.

Facts & Assumptions

Verification

technique · direct
1.1

The difference quotient at zero is f(x)/x=xsin⁡(1/x), whose absolute value is at most ∣x∣; hence f′(0)=0.

L1L2
1.2

For x≠0, product and chain rules give f′(x)=2xsin⁡(1/x)−cos⁡(1/x).

L1L2
2.1

Along rn=1/(2π(n+1)), the derivative tends to −1; along sn=1/((2n+1)π), it tends to 1.

step 1.2L1algebra
3.1

Both sequences tend to zero, so [L3] shows that f′ has no limit at zero and is not continuous there.

step 2.1L3∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

41 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources