Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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FALSE: spherical coordinates are globally injective

Statement

False claim. The spherical-coordinate map

S(r,ϕ,θ)=(rsin⁡ϕcos⁡θ, rsin⁡ϕsin⁡θ, rcos⁡ϕ)

is injective on [0,∞)×[0,π]×[0,2π].

The angular seam identifies θ=0 with θ=2π. At either polar angle, every azimuth represents the same point, and at radius zero both angles are lost. The Jacobian determinant

det⁡DS(r,ϕ,θ)=r2sin⁡ϕ

vanishes on the zero-radius and polar-axis loci.

Facts & Assumptions

Given: The map S:R3→R3 displayed in the Statement and its restriction to D=[0,∞)×[0,π]×[0,2π].

[L1]

The functions sin⁡ and cos⁡ are differentiable on R, with (sin⁡t)′=cos⁡t and (cos⁡t)′=−sin⁡t; also sin⁡0=0 and cos⁡0=1 (The derivatives of sine and cosine are cosine and minus sine).

[L2]

For every real t, sin⁡2t+cos⁡2t=1 (Parity and the Pythagorean identity for sine and cosine).

[L3]

Sine vanishes exactly at the integer multiples of π, and both sine and cosine have period 2π (The zero sets of sine and cosine and the least positive common period 2 pi).

[L4]

sin⁡(π/2)=1, cos⁡(π/2)=0, sin⁡π=0, and cos⁡π=−1 (Quarter-turn values and shifts by pi/2 and pi).

[L5]

For a C1 map g:R3→R3, its Jacobian matrix consists of its coordinate partial derivatives and its Jacobian determinant is det⁡Dg (The Jacobian determinant of a square-dimensional C1 map is the determinant of its Jacobian matrix).

[L6]

Finite componentwise products and composites of C1 Euclidean maps are C1 (Ck Euclidean maps are closed under componentwise algebra and composition).

[L7]
[L8]

For a real-valued function on A⊆R, differentiability at a limit point c∈A implies continuity there (A function differentiable at c is continuous at c).

Refutation

technique · direct
1.1givenL1L3L4L7

The two distinct points (1,π/2,0) and (1,π/2,2π) lie in D, and periodicity gives S(1,π/2,0)=S(1,π/2,2π)=(1,0,0).

1.2givenL1L3L4algebra

At ϕ=0, every θ∈[0,2π] gives S(r,0,θ)=(0,0,r); at ϕ=π, every such θ gives S(r,π,θ)=(0,0,−r); and S(0,ϕ,θ)=(0,0,0) for every pair of angles.

1.3L1L6L8

The coordinate functions of S are finite products and composites of coordinate maps with sine and cosine; their displayed derivatives are continuous, so S is C1.

2.1step 1.3L1L5algebra

Direct partial differentiation gives the following.

DS=(sin⁡ϕcos⁡θrcos⁡ϕcos⁡θ−rsin⁡ϕsin⁡θsin⁡ϕsin⁡θrcos⁡ϕsin⁡θrsin⁡ϕcos⁡θcos⁡ϕ−rsin⁡ϕ0)

3.1step 2.1L2algebra

Expanding the determinant in step 2.1 and using the Pythagorean identity gives det⁡DS=r2sin⁡ϕ.

4.1step 1.1step 1.2step 3.1L3∎

Step 1.1 already refutes global injectivity. Steps 1.2 and 3.1 show the additional pole and zero-radius identifications and show that the derivative is singular there, since r2sin⁡ϕ=0 when r=0, ϕ=0, or ϕ=π.

Remarks

Restricting the radius away from zero, the polar angle away from its endpoints, and the azimuth to a half-open interval removes these particular identifications. The false claim fails because the full closed parameter domain retains every seam and collapsed angular coordinate.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources