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Euclidean maps are closed under componentwise algebra and composition
Statement
Let . Finite componentwise sums and products of Euclidean maps are , and a composite of composable Euclidean maps is . Scalar multiples are included among the finite componentwise operations. The assertions remain valid on an empty open domain.
Facts & Assumptions
Given: Open Euclidean domains and maps for which the displayed sums, products, scalar multiples, or composites are defined. We use induction on derivative order (The principle of mathematical induction).
A map is of class when each component is of class ( Euclidean maps and diffeomorphisms).
If is totally differentiable at and is totally differentiable at , then is totally differentiable at and (The chain rule for total derivatives: ).
For differentiable real functions, sums and scalar multiples are differentiable with the expected derivatives, and (Sums, scalar multiples, products and quotients: , , , and when ).
If every first partial derivative exists near a point and is continuous there, then the map is totally differentiable there and its total derivative has matrix equal to its Jacobian (If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative).
Finite sums, products, and scalar multiples of continuous real functions are continuous (Sums, scalar multiples, products, absolute values, maxima, minima and quotients with nonvanishing denominator of continuous functions are continuous, as are constants, the identity and every polynomial function), and a composite of continuous maps between topological spaces is continuous (Continuity may be checked on any open cover, and on any finite closed cover; composites of continuous maps are continuous, claim 1).
Total differentiability gives every directional and partial derivative by applying the total derivative to the corresponding direction vector (A total derivative computes every directional derivative, and its matrix is the Jacobian).
Proof
At order , [F1] reduces the assertions to scalar component functions, and [L4] supplies closure under the stated operations; on an empty domain all these assertions are vacuous.
Fix and assume that all the closure assertions hold through order .
Consider maps of class . For a sum, scalar multiple, or componentwise product, [L2] on each coordinate line expresses every first partial derivative as a finite sum of products of functions. For a composite, [L3] supplies total differentiability, [L1] gives its total derivative, and [L5] identifies the first partials with the columns of that derivative; hence every first partial is a finite sum of products of first partials of the factors. The hypothesis in step 1.2 makes all these first partials , so [F1] makes the resulting maps . Together with the base case, this proves the result through every finite .
Depends on
- $C^k$ Euclidean maps and diffeomorphisms
- The chain rule for total derivatives: $D(g\circ f)(a)=Dg(f(a))\circ Df(a)$
- Sums, scalar multiples, products and quotients: $(f+g)'(c) = f'(c) + g'(c)$, $(\alpha f)'(c) = \alpha f'(c)$, $(fg)'(c) = f'(c)g(c) + f(c)g'(c)$, and $(f/g)'(c) = \bigl(f'(c)g(c) - f(c)g'(c)\bigr)/g(c)^{2}$ when $g(c) \ne 0$
- Sums, scalar multiples, products, absolute values, maxima, minima and quotients with nonvanishing denominator of continuous functions are continuous, as are constants, the identity and every polynomial function
- Continuity may be checked on any open cover, and on any finite closed cover; composites of continuous maps are continuous
- If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative
- A total derivative computes every directional derivative, and its matrix is the Jacobian
- The principle of mathematical induction
Used by
- The map (x,y)↦(x,xy) is a diffeomorphism off the vertical axis Example
- Two equations implicitly determine two variables near the origin Example
- Matrix inversion preserves Cᵏ regularity where the determinant is nonzero Lemma
- A local inverse of a Cᵏ regular map is Cᵏ Theorem
- The parametrized implicit function theorem with Cᵏ regularity Theorem
Dependency tree · two levels
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Sources
- J. Lebl, Basic Analysis II, §§8.5–8.6 (standard reference, not scraped)