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CorollaryStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-28
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A function differentiable at cc is continuous at cc

Statement

Let ARA \subseteq \mathbb{R}, let f:ARf : A \to \mathbb{R} and let cAc \in A be a limit point of AA (Limit point, isolated point, adherent point, derived set, and dense subset of R\mathbb{R}). If ff is differentiable at cc (The derivative f(c)=limxcf(x)f(c)xcf'(c) = \lim_{x \to c} \frac{f(x) - f(c)}{x - c} of f:ARf : A \to \mathbb{R} at a point cAc \in A that is a limit point of AA, and differentiability on a set) then ff is continuous at cc (Continuity of f:ARf : A \to \mathbb{R} at a point of AA and on AA: the ε\varepsilon-δ\delta condition, its agreement with limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c) at a limit point, and continuity at an isolated point).

Consequently, if ff is differentiable on a set SAS \subseteq A then ff is continuous at every point of SS.

No converse is asserted, and none holds. Continuity at cc does not give differentiability at cc, and the standard witness is worked out on the companion page.

Facts & Assumptions

[L1]

Carathéodory's characterisation (Carathéodory's characterisation: ff is differentiable at cc if and only if there is φ:AR\varphi : A \to \mathbb{R}, continuous at cc, with f(x)f(c)=φ(x)(xc)f(x) - f(c) = \varphi(x)(x - c) for every xAx \in A, and then φ\varphi is unique and φ(c)=f(c)\varphi(c) = f'(c)): since ff is differentiable at the limit point cc of AA, there is φ:AR\varphi : A \to \mathbb{R}, continuous at cc, with f(x)f(c)=φ(x)(xc)f(x) - f(c) = \varphi(x)(x - c) for every xAx \in A, and φ(c)=f(c)\varphi(c) = f'(c).

[L2]

Algebra of continuous functions (Sums, scalar multiples, products, absolute values, maxima, minima and quotients with nonvanishing denominator of continuous functions are continuous, as are constants, the identity and every polynomial function): sums, scalar multiples and products of functions continuous at a point of the common domain are continuous there (claim 1); and every constant function on AA and the identity xxx \mapsto x on AA are continuous at every point of AA (claim 5).

Proof

technique · direct
1.1

Fix a function φ:AR\varphi : A \to \mathbb{R}, continuous at cc, with f(x)f(c)=φ(x)(xc)f(x) - f(c) = \varphi(x)(x - c) for every xAx \in A.

L1choose
1.2

The identity xxx \mapsto x on AA and every constant function on AA are continuous at cc; hence so is xxcx \mapsto x - c, which is the sum of the identity and the constant function with value c-c.

L2
2.1

The pointwise product xφ(x)(xc)x \mapsto \varphi(x)(x - c) is continuous at cc, being the product of two functions on AA continuous at cc.

step 1.1step 1.2L2
3.1

For every xAx \in A one has f(x)=f(c)+φ(x)(xc)f(x) = f(c) + \varphi(x)(x - c), so ff is the sum of the constant function with value f(c)f(c) and the product of step 2.1.

step 1.1L1
4.1

A sum of two functions continuous at cc is continuous at cc, so ff is continuous at cc.

step 2.1step 3.1L2L3
5.1

The point cc was an arbitrary point of AA, a limit point of AA, at which ff is differentiable; applying step 4.1 at every point of a set SAS \subseteq A on which ff is differentiable gives continuity of ff at every point of SS.

step 3.1L3

Remarks

  • Where the work actually is. None of it is here. Carathéodory's characterisation already replaces the quotient by a product, and a product is visibly small when one factor is bounded near cc and the other tends to 00; the algebra of continuous functions packages exactly that. A direct proof from the quotient would multiply and divide by xcx - c and would have to say why that is legal, which is the same observation in a less convenient place.

  • The converse fails. xxx \mapsto |x| is continuous at 00 and not differentiable there, which is xxx \mapsto |x| is continuous everywhere and not differentiable at 00: the difference quotient equals 11 on the right and 1-1 on the left, so the two one-sided limits differ on the companion page. So continuity is strictly weaker, and the gap is not exotic: it opens at a single corner.

  • What is not claimed. Nothing here says that a function differentiable on a set has a continuous derivative, and nothing here says that ff' is defined anywhere except where it was assumed to be. Both are separate questions, and neither is settled on this page.

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 44 results over 16 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources