Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-28
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Carathéodory's characterisation: ff is differentiable at cc if and only if there is φ:AR\varphi : A \to \mathbb{R}, continuous at cc, with f(x)f(c)=φ(x)(xc)f(x) - f(c) = \varphi(x)(x - c) for every xAx \in A, and then φ\varphi is unique and φ(c)=f(c)\varphi(c) = f'(c)

Statement

Let ARA \subseteq \mathbb{R}, let f:ARf : A \to \mathbb{R} and let cAc \in A be a limit point of AA (Limit point, isolated point, adherent point, derived set, and dense subset of R\mathbb{R}). The following are equivalent.

  1. ff is differentiable at cc (The derivative f(c)=limxcf(x)f(c)xcf'(c) = \lim_{x \to c} \frac{f(x) - f(c)}{x - c} of f:ARf : A \to \mathbb{R} at a point cAc \in A that is a limit point of AA, and differentiability on a set).
  2. There is a function φ:AR\varphi : A \to \mathbb{R}, continuous at cc (Continuity of f:ARf : A \to \mathbb{R} at a point of AA and on AA: the ε\varepsilon-δ\delta condition, its agreement with limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c) at a limit point, and continuity at an isolated point), with f(x)f(c)  =  φ(x)(xc)for every xA.f(x) - f(c) \;=\; \varphi(x)\,(x - c) \qquad \text{for every } x \in A .

When they hold, the function φ\varphi of claim 2 is unique and satisfies φ(c)=f(c)\varphi(c) = f'(c).

What the reformulation buys. Claim 2 contains no quotient and no limit: it is an algebraic identity plus a continuity hypothesis at one point. Every differentiation rule on this page is proved by exhibiting the factor φ\varphi for the new function and reading its continuity off the algebra and composition theorems for continuous functions. In particular the chain rule becomes a one-line substitution, with none of the case analysis that the difference-quotient proof needs where the inner increment vanishes.

The hypothesis that cc is a limit point of AA is used in both directions. It is what makes f(c)f'(c) a defined symbol at all (The derivative f(c)=limxcf(x)f(c)xcf'(c) = \lim_{x \to c} \frac{f(x) - f(c)}{x - c} of f:ARf : A \to \mathbb{R} at a point cAc \in A that is a limit point of AA, and differentiability on a set), and it is what makes continuity of φ\varphi at cc equivalent to a statement about the limit of φ\varphi there (Continuity of f:ARf : A \to \mathbb{R} at a point of AA and on AA: the ε\varepsilon-δ\delta condition, its agreement with limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c) at a limit point, and continuity at an isolated point, clause 1). At an isolated point of AA claim 2 holds for every ff, with φ\varphi arbitrary off cc, because every function is continuous at an isolated point; claim 1 is not even a statement there.

Facts & Assumptions

Given: A set ARA \subseteq \mathbb{R}, a function f:ARf : A \to \mathbb{R} and a point cAc \in A that is a limit point of AA (Limit point, isolated point, adherent point, derived set, and dense subset of R\mathbb{R}).

[L1]

Differentiability at cc (The derivative f(c)=limxcf(x)f(c)xcf'(c) = \lim_{x \to c} \frac{f(x) - f(c)}{x - c} of f:ARf : A \to \mathbb{R} at a point cAc \in A that is a limit point of AA, and differentiability on a set): the difference quotient q(x):=(f(x)f(c))/(xc)q(x) := (f(x) - f(c))/(x - c) is a function on A{c}A \setminus \{c\}, the point cc is a limit point of A{c}A \setminus \{c\}, and ff is differentiable at cc exactly when limxcq(x)\lim_{x \to c} q(x) exists, its value then being f(c)f'(c); moreover, for any Q:ARQ : A \to \mathbb{R} agreeing with qq on A{c}A \setminus \{c\} and any real LL, the conditions limxcQ(x)=L\lim_{x \to c} Q(x) = L and limxcq(x)=L\lim_{x \to c} q(x) = L are the same condition, since the clause 0<xc0 < |x - c| removes x=cx = c from both quantifiers.

[L2]

The limit condition (The ε\varepsilon-δ\delta limit limxcf(x)=L\lim_{x \to c} f(x) = L of f:ARf : A \to \mathbb{R} at a limit point cc of AA): limxch(x)=L\lim_{x \to c} h(x) = L means that for every real ε>0\varepsilon > 0 there is a real δ>0\delta > 0 such that every xx in the domain of hh with 0<xc<δ0 < |x - c| < \delta satisfies h(x)L<ε|h(x) - L| < \varepsilon.

[L3]

Continuity at a limit point (Continuity of f:ARf : A \to \mathbb{R} at a point of AA and on AA: the ε\varepsilon-δ\delta condition, its agreement with limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c) at a limit point, and continuity at an isolated point, clause 1): for cAc \in A a limit point of AA, a function ψ:AR\psi : A \to \mathbb{R} is continuous at cc if and only if limxcψ(x)\lim_{x \to c} \psi(x) exists and equals ψ(c)\psi(c).

[L4]

At a limit point of its domain a function has at most one limit (At a limit point of the domain a function has at most one limit).

[L5]

Locality (claim 1 of The limit at cc depends only on the restriction of ff to a punctured neighbourhood of cc, and passes to any subset of the domain having cc as a limit point): if two functions on AA agree at every xAx \in A with 0<xc<η0 < |x - c| < \eta for some real η>0\eta > 0, then for every real LL one has limxc=L\lim_{x \to c} = L for the first exactly when it holds for the second.

Proof

technique · direct
1.1

Claim 1 implies claim 2: the factor. Assume ff is differentiable at cc, and define φ:AR\varphi : A \to \mathbb{R} by φ(x):=(f(x)f(c))/(xc)\varphi(x) := (f(x) - f(c))/(x - c) for xAx \in A with xcx \ne c, and φ(c):=f(c)\varphi(c) := f'(c). This is a function on the whole of AA, since every xAx \in A falls under exactly one of the two clauses and the division is by a nonzero number.

L1construct
1.2

Claim 2 implies claim 1: the hypothesis. Assume instead that some φ:AR\varphi : A \to \mathbb{R} is continuous at cc and satisfies f(x)f(c)=φ(x)(xc)f(x) - f(c) = \varphi(x)(x - c) for every xAx \in A.

assume-hyp
1.3

Uniqueness. Let φ\varphi and ψ\psi both be as in claim 2. For xAx \in A with xcx \ne c the identity gives φ(x)(xc)=f(x)f(c)=ψ(x)(xc)\varphi(x)(x - c) = f(x) - f(c) = \psi(x)(x - c), and dividing by xc0x - c \ne 0 gives φ(x)=ψ(x)\varphi(x) = \psi(x); so the two agree on A{c}A \setminus \{c\}, hence at every xAx \in A with 0<xc<10 < |x - c| < 1. By [L3] each has a limit at cc, equal to its own value there; by [L5] those two limits are limits of functions agreeing near cc, so by [L4] they are equal, that is φ(c)=ψ(c)\varphi(c) = \psi(c). Hence φ=ψ\varphi = \psi.

L3L4L5
2.1

The identity holds for the factor built in step 1.1. For xAx \in A with xcx \ne c, multiplying the defining equation φ(x)=(f(x)f(c))/(xc)\varphi(x) = (f(x) - f(c))/(x - c) by xcx - c gives φ(x)(xc)=f(x)f(c)\varphi(x)(x - c) = f(x) - f(c); and at x=cx = c both sides are 00, since f(c)f(c)=0f(c) - f(c) = 0 and φ(c)(cc)=0\varphi(c)(c - c) = 0. So the identity of claim 2 holds for every xAx \in A.

step 1.1
2.2

The factor built in step 1.1 is continuous at cc. That φ\varphi agrees with the difference quotient qq at every point of A{c}A \setminus \{c\} is its definition, so by [L1] the limit limxcφ(x)\lim_{x \to c} \varphi(x) exists and equals f(c)f'(c), which is φ(c)\varphi(c). Since cc is a limit point of AA, [L3] turns that into continuity of φ\varphi at cc.

step 1.1L1L3
2.3

Under the hypothesis of step 1.2, φ\varphi extends the difference quotient. For xAx \in A with xcx \ne c, dividing the identity by xc0x - c \ne 0 gives q(x)=φ(x)(xc)/(xc)=φ(x)q(x) = \varphi(x)(x-c)/(x-c) = \varphi(x). So φ\varphi agrees with qq at every point of A{c}A \setminus \{c\}.

step 1.2
2.4

Under the hypothesis of step 1.2, φ\varphi has a limit at cc. Continuity of φ\varphi at the limit point cc gives, by [L3], that limxcφ(x)\lim_{x \to c} \varphi(x) exists and equals φ(c)\varphi(c).

step 1.2L3
3.1

Claim 2 implies claim 1. By step 2.3 the function φ\varphi agrees with qq off cc, so the last clause of [L1] applies with Q:=φQ := \varphi and L:=φ(c)L := \varphi(c): from limxcφ(x)=φ(c)\lim_{x \to c} \varphi(x) = \varphi(c), given by step 2.4, it follows that limxcq(x)=φ(c)\lim_{x \to c} q(x) = \varphi(c). By [L1] again, ff is differentiable at cc and f(c)=φ(c)f'(c) = \varphi(c).

step 2.3step 2.4L1L2
4.1

Both implications and both supplementary claims are proved: claim 1 gives claim 2 by steps 1.1, 2.1 and 2.2, with φ(c)=f(c)\varphi(c) = f'(c) by construction; claim 2 gives claim 1 by step 3.1, with φ(c)=f(c)\varphi(c) = f'(c) established there; and the factor is unique by step 1.3.

step 1.1step 1.3step 2.1step 2.2step 3.1

Remarks

  • The identity at x=cx = c is empty, and that is the point. Both sides vanish there whatever φ(c)\varphi(c) is, so the identity alone determines φ\varphi only off cc; it is the continuity hypothesis that pins the remaining value, and it pins it to f(c)f'(c). Drop continuity and claim 2 becomes true for every ff whatsoever, with φ(c)\varphi(c) arbitrary.

  • Why this is not circular. The proof of claim 2 from claim 1 builds φ\varphi out of the very quotient whose limit is f(c)f'(c), so nothing new is asserted in that direction. The content is the other direction: a factorisation with a factor merely continuous at one point already forces the quotient to converge. That is the direction every rule on this page uses.

  • The factor is a genuinely useful object, not a device. For f(x)=xnf(x) = x^{n} it can be written down in closed form, as the polynomial φ(x)=k<nckxn1k\varphi(x) = \sum_{k < n} c^{k} x^{\,n-1-k} supplied by Factorisation of bnanb^n - a^n, and the resulting Lipschitz estimate; the companion page writes that factor out and differentiates a composite with it.

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 36 results over 15 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources