How statement and proof provenance work
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The solid generated by rotating on has volume
Example
Rotate the region
about the -axis. The resulting solid is compact and Jordan measurable, and its volume is
The vanishing endpoint radii are included in the solid and require no separate measurability argument.
Facts & Assumptions
Given: The profile on and its solid of revolution about the -axis.
If and is continuous, then its solid of revolution about the -axis is compact and Jordan measurable and has volume (The disc formula for the volume of a solid of revolution).
, and for every with ; thus is the first positive zero of sine, in particular (Pi is the first positive zero of sine).
The functions and are differentiable on , with and ; also and (The derivatives of sine and cosine are cosine and minus sine).
For a real-valued function on , differentiability at a limit point implies continuity there (A function differentiable at is continuous at ).
For every real , (Double-angle and quadratic power-reduction identities).
Every continuous real-valued function on a nondegenerate closed interval is Riemann integrable there (A continuous function on is Riemann integrable, by Heine-Cantor and Riemann's criterion).
The integral is linear on integrable functions (Integrable functions on form a set closed under sums and scalar multiples, and ).
If , every constant function on is integrable and (If on then for every partition ; in particular every constant function is integrable, with ).
If , is differentiable at every point of , and is integrable, then (The second fundamental theorem: if is differentiable on with and is integrable, then ).
If real functions and are differentiable at the relevant points, then (The chain rule, in one line from Carathéodory: if is differentiable at and is differentiable at , then is differentiable at with ).
Sums and scalar multiples obey the usual derivative rules (Sums, scalar multiples, products and quotients: , , , and when ).
Both sine and cosine have period (The zero sets of sine and cosine and the least positive common period 2 pi).
Verification
Facts [L1], [L2], and [L3] show that is continuous and nonnegative on , so [F1] makes the rotated solid compact and Jordan measurable and gives .
Since by [L1], the interval is nondegenerate. The function is differentiable with , and this derivative is continuous and therefore integrable on .
On the same nondegenerate interval, the constant function is integrable and has integral .
By power reduction and linearity, followed by the fundamental theorem applied to step 1.2, , because periodicity and [L2] give .
Substituting step 2.1 into the disc formula of step 1.1 gives .
Remarks
The profile radius vanishes at both endpoints, but [F1] permits nonnegative continuous profiles and explicitly includes zero-radius sections. No division by the profile occurs.
Depends on
- The disc formula for the volume of a solid of revolution
- Pi is the first positive zero of sine
- A function differentiable at $c$ is continuous at $c$
- Double-angle and quadratic power-reduction identities
- A continuous function on $[a,b]$ is Riemann integrable, by Heine-Cantor and Riemann's criterion
- Integrable functions on $[a,b]$ form a set closed under sums and scalar multiples, and $\int_a^b(\lambda f+\mu g) = \lambda\int_a^b f + \mu\int_a^b g$
- If $m \le f \le M$ on $[a,b]$ then $m(b-a) \le L(f,P) \le \underline{\int_a^b} f \le \overline{\int_a^b} f \le U(f,P) \le M(b-a)$ for every partition $P$; in particular every constant function is integrable, with $\int_a^b c = c(b-a)$
- The second fundamental theorem: if $G$ is differentiable on $[a,b]$ with $G' = f$ and $f$ is integrable, then $\int_a^b f = G(b)-G(a)$
- The derivatives of sine and cosine are cosine and minus sine
- The chain rule, in one line from Carathéodory: if $g$ is differentiable at $c$ and $f$ is differentiable at $g(c)$, then $f \circ g$ is differentiable at $c$ with $(f \circ g)'(c) = f'(g(c))\,g'(c)$
- Sums, scalar multiples, products and quotients: $(f+g)'(c) = f'(c) + g'(c)$, $(\alpha f)'(c) = \alpha f'(c)$, $(fg)'(c) = f'(c)g(c) + f(c)g'(c)$, and $(f/g)'(c) = \bigl(f'(c)g(c) - f(c)g'(c)\bigr)/g(c)^{2}$ when $g(c) \ne 0$
- The zero sets of sine and cosine and the least positive common period 2 pi
Used by
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Sources
- OpenStax, Calculus Volume 2, section 2.2 Determining Volumes by Slicing (standard reference, not scraped)
- J. Lebl, Basic Analysis II, section 11.4 Complex exponential and trigonometric functions (standard reference, not scraped)