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Finite tori are compact Hausdorff spaces separated by characters

Statement

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)) and let T=R/Z be the torus with quotient map q and quotient topology (The one-dimensional torus and its normalized Haar integral, The quotient topology of a surjection, quotient maps, saturated sets, and the quotient of a space by an equivalence relation with its canonical projection).

  1. T is compact (Open cover, subcover, and compact topological space; a compact subset is a subspace that is compact in its own right) and Hausdorff (Hausdorff space: distinct points have disjoint open neighbourhoods; every metrizable space is Hausdorff and the indiscrete topology on two points is not), and the map φ:TS1,φ([t]):=(cos2πt, sin2πt), is a well-defined homeomorphism onto the Euclidean unit circle S1={(x,y)R2:x2+y2=1}.
  2. For every natural n1 the finite torus Tn is compact and Hausdorff in the finite product topology (The one-dimensional torus and its normalized Haar integral), and the coordinate characters separate its points. Explicitly, define χj(x):=exp(2πit) using any real representative t with q(t)=xj; this is well defined, and for distinct x,yTn some j<n satisfies χj(x)χj(y) (The complex exponential by its power series).

Facts & Assumptions

[A3]

t(cost,sint) is a bijection of [0,2π) onto S1; sine and cosine have least positive common period 2π, hence cos(x+2πm)=cosx and sin(x+2πm)=sinx for every integer m, and exp(iθ)=cosθ+isinθ (t(cost,sint) is a bijection from [0,2π) onto the real unit circle, The zero sets of sine and cosine and the least positive common period 2 pi, exp(x+iy)=ex(cosy+isiny), exp(x+iy)=ex, and eiπ+1=0).

[A4]

exp(2πiu)=exp(2πiv) for reals u,v if and only if uvZ, because both sides have the cartesian form of [A3] and the parametrisation of the circle is injective on [0,2π) (exp(x+iy)=ex(cosy+isiny), exp(x+iy)=ex, and eiπ+1=0, t(cost,sint) is a bijection from [0,2π) onto the real unit circle).

[A5]

A finite product of compact spaces is compact, and arbitrary products preserve the Hausdorff property (A product of finitely many compact spaces is compact in the product topology, Arbitrary products preserve T0, T1, and Hausdorffness).

[A7]

With S:=kZ(tδ+k, t+δ+k) and T:=kZ(sδ+k, s+δ+k) for δ:=dist(st,Z)/2>0 when stZ, the two unions are disjoint saturated open sets, so their images are disjoint open neighbourhoods (The quotient topology of a surjection, quotient maps, saturated sets, and the quotient of a space by an equivalence relation with its canonical projection); and an integer part satisfies nr<n+1 (Integer part: for every real x there is exactly one integer m with mx<m+1).

Proof

technique · direct

Given: Countable Choice, the torus T=R/Z with quotient map q, and the map φ.

1.1

T is compact: [0,1] is compact, q is continuous, and every class has a representative in [0,1], so T=q([0,1]) is a continuous image of a compact space.

A1
1.2

T is Hausdorff: let [s][t], so that stZ and δ:=dist(st,Z)/2>0 (positive because for x:=st and an integer part n of x one has xmmin(xn, n+1x)>0 for every mZ). The saturated open sets of [A7] are the preimages of neighbourhoods of [s] and [t] and are disjoint, so the two classes have disjoint open neighbourhoods.

A7
1.3

φ is well defined and continuous: if ttZ then t=t+m and 2πt=2πt+2πm, so periodicity gives the same pair (cos,sin); the map t(cos2πt,sin2πt) is continuous, being built from sine and cosine, which are differentiable and hence continuous, by composition with the continuous linear multiplication by 2π, and it is constant on the fibres of q, so it induces a continuous φ by the universal property.

A3A6
1.4

The coordinate character χj(x):=exp(2πit), where tR is any representative with q(t)=xj, is well defined by [A4]. If xy in Tn, then xjyj for some j<n. Were χj(x)=χj(y), [A4] would make the difference of chosen real representatives an integer and hence force xj=yj, a contradiction. Thus the coordinate characters separate points.

A4
2.1

φ is bijective: it is surjective because every point of S1 is (cosθ,sinθ) for some θ[0,2π) and then θ/(2π)[0,1) represents a class mapping to it; and it is injective because if φ([s])=φ([t]), then choosing representatives s,t[0,1) of the two classes and using periodicity gives (cos2πs,sin2πs)=(cos2πt,sin2πt) with 2πs,2πt[0,2π), so 2πs=2πt by injectivity of the parametrisation, whence [s]=[t].

step 1.3A3
2.2

For n1 the finite torus Tn is a finite product of compact Hausdorff spaces, hence compact Hausdorff, by [A5], step 1.1 and step 1.2.

step 1.1step 1.2A5
3.1

By steps 1.1, 1.2 and 2.1, φ is a continuous bijection from the compact space T onto the Hausdorff Euclidean circle S1, hence a homeomorphism, which is claim 1.

step 1.1step 1.2step 2.1A2
4.1

Steps 3.1, 2.2 and 1.4 establish the homeomorphism φ, compactness and Hausdorffness of every finite torus, and separation of points by the coordinate characters.

step 1.4step 2.2step 3.1

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