Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (z-ai/glm-5.2)audited 2026-07-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Arbitrary products preserve T0T_0, T1T_1, and Hausdorffness

Statement

For any family (Xi)iI(X_i)_{i\in I}, if every XiX_i is T0T_0, respectively T1T_1, respectively Hausdorff, then iIXi\prod_{i\in I}X_i is respectively T0T_0, T1T_1, respectively Hausdorff. The empty product is included.

Facts & Assumptions

Proof

technique · direct
1.1

If I=I=\varnothing, the product has one point and all three conditions hold vacuously.

F2
1.2

Otherwise choose iIi\in I with xiyix_i\ne y_i. For a T0T_0 factor, the inverse image under πi\pi_i of an open set distinguishing xi,yix_i,y_i distinguishes x,yx,y.

F1F2
1.3

For a T1T_1 factor, pull back the two open sets separating xix_i from yiy_i and yiy_i from xix_i.

F1F2
1.4

For a Hausdorff factor, pull back disjoint open neighbourhoods of xi,yix_i,y_i; their inverse images remain disjoint.

F1F2
2.1

Thus the product has the relevant property in every case.

step 1.1step 1.2step 1.3step 1.4

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 60 results over 12 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources