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The Kunneth short exact sequence has no generally canonical splitting
Statement
The assertion that the Kunneth short exact sequence has a canonical splitting is false.
Refutation
Given: let , with , , and let , with .
We have , , and . In total degree one the Kunneth sequence is therefore . Writing , a direct kernel/modulo-boundary calculation gives ; the left Kunneth term is generated by and the quotient by the class of .
The chain automorphism , , of induces the identity on , hence on both outer Kunneth terms, but sends to in the middle term.
Every section of the quotient sends its generator to for some . Naturality under would require this lift to be fixed, but changes to . Thus no splitting of all Kunneth sequences can be canonical or natural.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Weibel, An Introduction to Homological Algebra (standard reference, not scraped)