Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-27
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FALSE: the same delta works after every finite change of generating set

Statement

False claim: once a finitely generated group is hyperbolic, one numerical slimness constant δ works for the Cayley graph of every finite generating set.

Facts & Assumptions

Given: The free group F2=a,b and, for each integer n2, the generating set Sn={a,b,anbn}.

[L1]

Hyperbolicity is independent of the generating set, but only up to quasi-isometry (Hyperbolicity of a finitely generated group is independent of the finite generating set).

[A1]

In the Cayley graph of (F2,Sn), the vertices 1, an, and anbn form a geodesic triangle with side lengths n, n, and 1.

Refutation

technique · direct
1.1

The generating set {a,b} gives a tree Cayley graph, so F2 is 0-hyperbolic for that choice.

given
1.2

Let δ0, and choose n>2δ+2. By [A1], the side from 1 to an is geodesic in the Cayley graph of (F2,Sn). Write k=n/2. Any word from ak to anbn has abelianization (nk,n); using the generator anbn once leaves (k,0) and therefore still needs at least k letters, while using it zero times needs at least n letters. Hence d(ak,anbn)k+1, so the distance from ak to the one-edge side [1,anbn] is at least k>δ. Its distance to the side [an,anbn] is nk>δ. So this geodesic triangle is not δ-slim.

A1choosealgebra
2.1

Since δ was arbitrary, no single constant works for all finite generating sets of F2. The theorem [L1] preserves only existence of some constant for each generating set separately. Therefore the claim is false.

L1step 1.1step 1.2

Depends on

Used by

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Dependency tree · two levels

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Sources