Alphabeta Math
False statementConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedaudited 2026-09-22
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False: ZFC proves the normal Moore space conjecture

Statement

Relative to Con(ZFC), it is false that ZFC proves the normal Moore space conjecture: ZFC does not prove that every normal Moore space is metrizable.

Facts & Assumptions

Given: The metatheoretic hypothesis Con(ZFC) and the fixed arithmetization of The standard certified provability predicate.

[F1]

Con(ZFC) implies Con(ZFC+CH) (Positive relative consistency of CH and GCH).

[F2]

Weakening, concatenation, and replacement of proved sentence premises by their proofs preserve derivability (Finite support, weakening, and composition of derivations).

[F3]

ZFC+CH proves that there is a normal nonmetrizable Moore space (CH yields a normal nonmetrizable Moore space, Moore spaces and developments).

[F4]

NMSC is the assertion that every normal Moore space is metrizable. [given]

Refutation

technique · direct
1.1

Assume Con(ZFC). Then Con(ZFC+CH) directly by [F1].

givenF1
2.1

If ZFC proved NMSC, weakening would give the same theorem in ZFC+CH. But [F3] gives in that theory a normal nonmetrizable Moore space, contradicting NMSC; by the proof-composition operations of [F2], these two finite derivations concatenate to a ZFC+CH refutation, contrary to [step 1.1].

step 1.1F2F3F4
3.1

Therefore, assuming Con(ZFC), no such refutation exists and ZFC does not prove NMSC.

step 2.1discharge-contradiction

Remarks

Depends on

Used by

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Dependency tree · two levels

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Sources