How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Duality and nesting of the A_p classes
Statement
Assume the Axiom of Countable Choice (The Axiom of Countable Choice ()).
Let be a weight on (Weights, their associated measures, and the spaces L^p(w)). Then:
- For , if and only if its reciprocal power lies in , where , and then (Conjugate exponents, including the endpoint conventions).
- The classes are nested: for with , and for every with for a dimensional constant .
Facts & Assumptions
Given: Countable Choice; A weight and the characteristic constants of Muckenhoupt A_p and A_1 weights.
The condition is equivalent to the cube-average/essential-infimum form: there is a dimensional constant with for every cube , and conversely the cube-average form with constant gives (The two defining forms of A_1 agree).
Hölder's inequality with conjugate exponents and the generalized form for finitely many factors hold for nonnegative measurable functions; in particular for and nonnegative measurable (Holder's inequality for integrals, including the endpoint cases, Generalized Holder inequality puts products into ).
Proof
Set . Since , one has , and therefore for every cube . Taking suprema, the two suprema are finite simultaneously and ; if , finiteness of its product and positivity of imply local integrability of , so is a weight. Conversely, if , the displayed identity gives the bound for the already given weight .
For put and , so that . By the power-mean inequality of [F2], for every cube ; raising to the -th power gives .
For and every cube , put . By [F1], . For every , a.e. on , so . Taking suprema proves with the stated bound for the entire range .
Combining step 1.2 with the definition, for every cube one has ; taking the supremum in gives and in particular for .
Steps 2.1 and 1.3 are the two nesting assertions, and step 1.1 is the duality assertion together with the exact identity of characteristics; this proves the lemma with .
Depends on
- Muckenhoupt A_p and A_1 weights
- The two defining forms of A_1 agree
- Holder's inequality for integrals, including the endpoint cases
- Generalized Holder inequality puts products into $L^r$
- Conjugate exponents, including the endpoint conventions
- Weights, their associated measures, and the spaces L^p(w)
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
Dependency tree · two levels
39 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Loukas Grafakos, Classical Fourier Analysis, 3rd ed. (Springer GTM 249, 2014) (standard reference, not scraped)
- Juha Kinnunen, Harmonic Analysis (Aalto University lecture notes) (standard reference, not scraped)