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A smooth exhaustion separates the locally finite chart bands
Statement
Let be a noncompact smooth manifold. Then there exist a smooth proper function , compact bands and smooth maps such that:
- each is supported in a neighbourhood of ;
- the supports of and are disjoint whenever and ;
- separates points and tangent vectors on ; and
- everywhere.
Facts & Assumptions
Given: A noncompact smooth -manifold .
The manifold admits a smooth proper exhaustion function (Every smooth manifold admits a smooth proper exhaustion function).
A closed set inside an open set admits a smooth cutoff equal to near the closed set and supported in the open set (A smooth Urysohn lemma for a closed set in an open set).
A smooth manifold comes with smooth coordinate charts (Smooth manifolds and their smooth charts).
Smooth maps that agree on overlaps paste over an open cover (Smooth maps paste over an open cover).
Proof
Choose a nonnegative smooth proper exhaustion from [L1]. Let Each is compact and the family covers . If and , the defining intervals are separated by a positive gap.
Put . Then , and for distinct congruent indices modulo . If , take and ; all four requirements for this index are then immediate. Henceforth suppose .
For every , a chart from [F1] can be shrunk over a Euclidean ball to a coordinate domain with , compact closure, and . Applying [L2] to gives a smooth supported in and equal to on an open neighbourhood of . The collection of all plateau neighbourhoods obtainable in this way covers , so compactness selects finitely many data , , whose cover .
For each selected datum define a global block by On the open cover the two formulas are smooth and agree on the overlap, so [L3] makes smooth. Set . Its support lies in the finite union of the compact sets .
The map separates points of : if , choose with . Equality of the first coordinate of the th block gives , and equality of the remaining coordinates gives , whence . It also separates tangent vectors: for , the function is locally constant with value , so the last components of are , an isomorphism. Thus is injective for every .
Compact support makes bounded. Choose with for every , and put This positive rescaling preserves support and both separation properties, and it gives everywhere.
For a nonempty band, steps 4.1 and 6.1 put inside ; for an empty band, step 2.1 gives empty support. The sets are disjoint for distinct congruent indices modulo , so the corresponding supports are disjoint. Together with steps 1.1, 5.1, and 6.1, this proves all four stated properties.
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Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- John M. Lee, Introduction to Smooth Manifolds, 2nd ed., Chapter 6 (standard reference, not scraped)
- Marco Gualtieri, Topology I: Smooth Manifolds, Part 11 (standard reference, not scraped)