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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

AC supplies the dependent-choice instances used in vector-bundle constructions

Statement

In ZF, the Axiom of Choice implies the prescribed-initial-point form of the Axiom of Dependent Choice. Explicitly, if X is nonempty, R is an entire relation on X, and aX, then AC supplies a sequence x:NX such that

x0=aandxnRxn+1

for every nN. Consequently, a vector-bundle theorem stated under AC may discharge a separately declared DC hypothesis without assuming another choice principle.

Facts & Assumptions

Given: ZF, AC, a nonempty set X, a relation R entire on X, and a prescribed point aX.

[F1]

AC says that every family of nonempty sets has a choice function (The Axiom of Choice).

[F2]

DC with prescribed initial point asks for a function x:NX with x0=a and xnRxn+1 for every n (The axiom of dependent choice: a relation in which every element is related to something admits an N-indexed chain).

[F3]

Given a set X, a point aX, and a function s:XX, recursion on N supplies a unique function x:NX with x0=a and xn+1=s(xn) (The recursion theorem).

Proof

technique · direct
1.1

For each uX, let Su={vX:uRv}. Every Su is nonempty because R is entire. Apply [F1] to the set S={Su:uX} and let c be its choice function. Define s:XX by s(u)=c(Su). This is well-defined even when two successor sets coincide, and uRs(u) for every uX.

F1givenconstruct
2.1

Apply [F3] to s and the prescribed a. It gives x:NX with x0=a and xn+1=s(xn). Step 1.1 then gives xnRxn+1 for every n.

F3step 1.1
3.1

Since X, the entire relation R, and a were arbitrary, the sequence in step 2.1 satisfies exactly the prescribed-initial-point formulation in [F2]. Thus AC implies DC, and every later use of this lemma spends AC only in the simultaneous choice made in step 1.1.

F2step 1.1step 2.1

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources