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A petite drift enlargement is small under aperiodicity

Statement

Let P be countably generated, ϕ-irreducible and aperiodic with invariant probability π. Suppose D is petite with probability ν and multiplier α>0, and C⊆D is (m,ϵ,ν)-small for this same ν, with ν(C)>0 and ν≪π. Then D is small at some common time.

Facts & Assumptions

Given: The kernel, irreducibility, aperiodicity, invariant probability, petite inequality on D, and same-measure small-set minorization on C.

[F1]

Petite sets for a Markov kernel: ∑n≥1anPn(x,⋅)≥αν(⋅) on D.

[F2]

Small-set minorization and geometric drift: Pm(y,⋅)≥ϵν on C.

[F3]

Aperiodicity makes minorization times eventually consecutive: once every state can reach a minorization into ν≪π, νPn≥cnν for every sufficiently large n.

[F4]

Phi-irreducibility for a general-state Markov kernel: every positive-ϕ set is accessible from every state.

[F5]

Discrete strong Markov property: the chain restarts from its state at the first entrance time.

[F6]

Invariant and stationary distribution for a Markov kernel: πPn=π for every n≥0.

[A1]

The Axiom of Choice: the canonical path/stopping-time construction uses AC as specified by [F5].

Proof

Given: The hypotheses and facts [F1]–[F5], with [A1].

1.1F1given

The petite inequality on C gives ∑nanPn(x,C)≥αν(C)>0 for every x∈D. Choose M so ∑n>Man<αν(C)/2. Since Pn(x,C)≤Pr⁡x(τC≤n)≤Pr⁡x(τC≤M) for n≤M, the truncated weighted sum gives Pr⁡x(τC≤M)≥q:=αν(C)/2 uniformly on D.

2.1F2F3F4F6step 1.1

Since ν(C)>0 and ν≪π, π(C)>0. To see that every state has positive probability of reaching C, let H={x∈Cc:Pn(x,C)=0 for every n≥1}. Kernel iteration makes H measurable. If x∈H and P(x,Hc)>0, the countable union Hc=C∪⋃n≥1{y:Pn(y,C)>0} has a member of positive P(x,⋅)-mass; integrating the corresponding positive function gives Pn+1(x,C)>0, a contradiction. Thus P(x,H)=1 for every x∈H. Suppose H≠∅ and fix x∈H. Irreducibility then forces ϕ(Hc)=0, since no point of H can reach Hc; hence ϕ(H)>0. For every n≥1, invariance and Pn(x,H)=1 on H give ∫HcPn(x,H) π(dx)=0. Irreducibility says every x∈Hc has Pn(x,H)>0 for some n, so the countable union of these π-null level sets is Hc and π(Hc)=0, contradicting π(C)>0. Therefore H=∅. For x∉C some positive time reaches C by the definition of H; for x∈C, [F2] gives Pm(x,C)≥ϵν(C)>0. Thus for each state there is n(x)≥1 with Pn(x)(x,C)>0; then Pn(x)+m(x,⋅)≥ϵPn(x)(x,C)ν(⋅). By [F3], νPt≥ctν for every t≥N0. Choose L>M+m+N0. For every 0≤s≤M and y∈C, PL−s(y,⋅)≥ϵνPL−s−m(⋅)≥ϵcL−s−mν(⋅). The minimum c>0 over these finitely many s is positive.

3.1F5A1step 1.1step 2.1∎

Decompose at the first hitting time τC=s≤M. The strong Markov property and step 2.1 give PL(x,⋅)≥cν(⋅)Pr⁡x(τC≤M)≥cqν(⋅) for every x∈D. This is one fixed-time minorization, so D is small.

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