Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

In a connected locally finite graph every ball of the path metric is finite

Statement

In a connected locally finite graph every ball of the path metric is finite.

Facts & Assumptions

Given: The hypotheses of the Statement.

[F1]

A graph is locally finite when every vertex has finitely many neighbours (Locally finite graphs and vertex degree without a finiteness hypothesis).

[L1]

The path metric of a connected simple graph assigns to two vertices the least length of a path joining them (The path metric of a connected simple graph).

[L2]

B(x,r) is the open ball, Bˉ(x,r) the closed ball and S(x,r) the sphere of centre x and radius r. The radius is always a strictly positive real; a ball of radius 0 or of negative radius is never written in this library. (Open ball, closed ball and sphere in a metric space).

[L3]

A walk of length ℓ in a simple graph is a finite vertex list (v0,…,vℓ) with consecutive vertices adjacent; a path is a walk with distinct vertices; the graph is connected when it is nonempty and every two vertices are joined by a path (Walks, paths, connectedness and components in a simple graph on an arbitrary vertex set).

[L4]

A set A is finite when A≈n for some n∈N. (The cardinality ∣A∣ of a finite set).

[L5]

Every complete ordered field is Archimedean: for every real x there is a natural number n≥1 with x<n (Every complete ordered field is Archimedean).

Proof

technique · induction
1.1L1base

Fix a vertex x. For each natural number n let Cn:={ y:dG(x,y)≤n }. Then C0={x}, so C0 is finite.

1.2F1L1L3L4ih

Assume Cn is finite. If y∈Cn+1, choose a path (v0,…,vm) from x to y of minimal length m=dG(x,y)≤n+1. If m=0 then y=x∈Cn. If m≥1, then vm−1∈Cn and y lies in NG(vm−1)∪{vm−1}. Hence Cn+1⊆⋃v∈Cn(NG(v)∪{v}). Each set NG(v)∪{v} is finite by local finiteness, so the right-hand side is a finite union of finite sets and is therefore finite; thus Cn+1 is finite.

2.1step 1.2

By step 1.2, if Cn is finite then so is Cn+1.

3.1L1L2L5L6step 1.1step 2.1discharge-induction∎

Therefore every Cn is finite. Now let r>0. By the Archimedean property choose a natural number N≥1 with r<N. Because dG(x,y) is the length of a path, it is a natural number; so dG(x,y)<r<N implies dG(x,y)≤N−1. Hence B(x,r)⊆CN−1, and [L6] makes B(x,r) finite.

Depends on

Used by

Dependency tree · two levels

33 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources