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Exact projections onto linkage blocks preserve projectives

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let C be a linkage class and let pr⁡C:O→OC be the exact projection of the block decomposition of Central-character summands refine into linkage blocks, i.e. the functor that keeps the direct summand supported on C.

If P∈O is projective (Projective object), then pr⁡C(P) is projective in O. Conversely, if Q∈OC is projective in the full subcategory OC, then Q is projective in O. The proof is the two adjunction identities Hom⁡O(pr⁡CP,X)=Hom⁡O(P,X) for X∈OC and Hom⁡O(Q,X)=Hom⁡OC(Q,pr⁡CX) for general X∈O, together with exactness of pr⁡C; these reduce exactness of Hom⁡ to the corresponding exactness in OC or in O.

Facts & Assumptions

Given: The Axiom of Choice, a linkage class C, and the block decomposition of O into the subcategories OC.

[F1]

Partition the simple labels into the linkage classes. Every extension of two simples from distinct classes splits, in either order (Simple extensions cannot cross linkage classes); consequently every object X of O has a unique decomposition X=⨁CXC into subobjects whose composition factors lie in C, with finitely many nonzero terms, functorial in X, and every morphism between objects supported on disjoint collections of classes is zero (Splitting finite-length modules across separated simple classes, Central-character summands refine into linkage blocks). Write XC=pr⁡C(X) and let iC be the embedding of the full subcategory OC (Generalized central-character decomposition of O). In particular P≅pr⁡C(P)⊕⨁D≠Cpr⁡D(P).

[F2]

An object P of an abelian category is projective precisely when Hom⁡(P,−) preserves epimorphisms, equivalently is exact; and every epimorphism onto a projective splits (Projective object, Projective object characterisations).

[F3]

In an abelian category, finite direct sums are biproducts: for morphisms fD:XD→YD the kernel and image of the block-diagonal morphism ⨁DfD are ⨁Dker⁡fD and ⨁Dim⁡fD, so a chain complex of decomposed objects with block-diagonal differentials is exact exactly when each D-component is exact.

Proof

technique · direct, through the functorial block decomposition and the $\operatorname{Hom}$ characterisation of projectivity
1.1givenF1

By [F1] every object X is ⨁CXC with finitely many nonzero terms, the decomposition is functorial, and morphisms between objects supported on disjoint collections of classes vanish. Hence a morphism f:X→Y between decomposed objects is block diagonal, f=⨁CfC with fC:XC→YC.

1.2givenF2

By [F2] the projectivity of P in O says exactly that Hom⁡O(P,−) is exact on O, and the hypothesis on Q says that Hom⁡OC(Q,−) is exact on OC.

2.1F3step 1.1algebra

Apply [F3] to the block-diagonal differentials of step 1.1: a short exact sequence 0→A→E→B→0 in O decomposes into the short exact sequences 0→AC→EC→BC→0 of its components, and conversely exactness of all components gives exactness of the sequence. Therefore pr⁡C is an exact functor O→OC, and iC is exact as the inclusion of a full subcategory closed under subobjects and quotients.

2.2givenF1step 1.1

For A∈OC and any X∈O, decomposing X and using the vanishing of morphisms from A into components supported on other classes gives a natural isomorphism Hom⁡O(A,X)≅Hom⁡OC(A,pr⁡CX); here Hom⁡O(iCA,X) is written Hom⁡O(A,X). Similarly, for Y∈OC, decomposing P gives Hom⁡O(P,pr⁡CY)≅Hom⁡O(pr⁡CP,pr⁡CY), because all components of P other than pr⁡CP map to zero into the object pr⁡CY of OC.

3.1F2step 1.2step 2.1step 2.2

Let P∈O be projective. Composing the isomorphisms of step 2.2, for every X∈O there is a natural isomorphism Hom⁡O(pr⁡CP,X)≅Hom⁡OC(pr⁡CP,pr⁡CX)≅Hom⁡O(P,pr⁡CX). Now X↦pr⁡CX is exact by step 2.1 and Hom⁡O(P,−) is exact by step 1.2, so the composite functor X↦Hom⁡O(pr⁡CP,X) is exact. By [F2] applied in O, pr⁡CP is projective in O.

4.1F2step 1.2step 2.1step 2.2∎

Conversely let Q∈OC be projective in OC. By step 2.2, for every X∈O there is a natural isomorphism Hom⁡O(Q,X)≅Hom⁡OC(Q,pr⁡CX). The first functor is the composite of the exact functor pr⁡C of step 2.1 with the exact functor Hom⁡OC(Q,−) of step 1.2, hence is exact; by [F2], Q is projective in O.

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