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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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Calderón–Zygmund decomposition at height λ

Statement

Assume Countable Choice. Let f∈L1(Rn) and λ>0. Then f=g+∑jbj almost everywhere, where the cubes Qj are the maximal all-generation dyadic cubes of Maximal dyadic cubes above a level, bj=(f−∣Qj∣−1∫Qjf)1Qj satisfies ∫bj=0 and ∥bj∥1≤2n+1λ∣Qj∣, and g=f outside ⋃jQj,g=∣Qj∣−1∫Qjf on Qj satisfies ∥g∥1≤∥f∥1, ∣g∣≤2nλ almost everywhere, and ∥g∥22≤2nλ∥f∥1; moreover ∑j∣Qj∣≤λ−1∥f∥1.

Facts & Assumptions

Given: f∈L1(Rn) and λ>0; the maximal bad dyadic cubes Qj of the previous lemma, pairwise disjoint with ∑j∣Qj∣≤λ−1∥f∥1 and ∣Qj∣−1∫Qj∣f∣≤2nλ; the functions g and bj defined above.

[F1]

The maximal bad cubes Qj (cubes with ∣Q∣−1∫Q∣f∣>λ, maximal under inclusion) are countable, pairwise disjoint, have union {Mdf>λ}, and satisfy ∣Qj∣−1∫Qj∣f∣≤2nλ and ∑j∣Qj∣≤λ−1∥f∥1 (Maximal dyadic cubes above a level).

[F2]

A family (Er)r>0 shrinks nicely to x with constant α when Er⊆B(x,r) and λ(Er)≥αλ(B(x,r)); if for each x in a set A such a family is given, then for almost every x∈A the averages of an Lloc1 function over Er converge to the function value as r→0+ (Differentiation holds along families shrinking nicely, Almost every point is a Lebesgue point of a locally integrable function).

Proof

technique · direct
1.1F1givenalgebra

The functions g and bj are measurable, bj is supported in Qj, and f=g+∑jbj everywhere: on Qj the sum g+∑kbk has the single nonzero term g+bj=∣Qj∣−1∫Qjf+f−∣Qj∣−1∫Qjf=f by disjointness of the Qk, while off ⋃kQk one has g=f and every bk=0. Moreover ∫bj=∫Qjf−∣Qj∣−1∫Qjf ∣Qj∣=0 and ∥bj∥1≤∫Qj∣f∣+∣Qj∣−1∣∫Qjf∣∣Qj∣≤2∫Qj∣f∣≤2⋅2nλ∣Qj∣=2n+1λ∣Qj∣.

2.1F1F2step 1.1algebra

On each bad cube, ∣g∣=∣Qj∣−1∣∫Qjf∣≤∣Qj∣−1∫Qj∣f∣≤2nλ, so ∣g∣≤2nλ on ⋃jQj; off ⋃jQj one has g=f and all dyadic cubes through x are good, so the averages of ∣f∣ over those cubes are at most λ. These cubes, indexed by generation and assigned to the parameter r=2n 2−k for the generation-k cube through x and extended constantly on [2n 2−k,2n 2−k+1), shrink nicely to x with a dimensional constant: each lies in B(x,r) and has measure 2−kn=cnλ(B(x,2n2−k)). Hence [F2] gives ∣f(x)∣≤λ for almost every x∉⋃jQj, and since g=f there, ∣g∣≤max⁡(2nλ,λ)=2nλ almost everywhere.

3.1F1step 1.1step 2.1algebra∎

From step 2.1, ∥g∥1≤∫⋃Qj∣g∣+∫Rn∖⋃Qj∣f∣≤∑j∫Qj∣f∣+∫Rn∖⋃Qj∣f∣=∥f∥1, and ∥g∥22=∫∣g∣2≤∥g∥∞∫∣g∣≤2nλ∥f∥1. Together with step 1.1 and the bounds ∑j∣Qj∣≤λ−1∥f∥1 and ∣Qj∣−1∫Qj∣f∣≤2nλ from [F1], this is the asserted decomposition.

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