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LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
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Cauchy estimates propagate from a compact set to its hull

Statement

Let ΩCm be a domain, let KΩ be compact, let 0<r<δΩ(K), and define

Kr:=aKΔr(a).

Then KrΩ. Moreover, for every holomorphic f on Ω and every multi-index α,

supwK^Ωαf(w)α!r(α1++αm)supzKrf(z).

Facts & Assumptions

Given: A nonempty compact set KΩ, a number 0<r<δΩ(K), and fO(Ω).

[L1]

The hull K^Ω is characterized by the inequalities against holomorphic functions on Ω (Holomorphic hulls and holomorphic convexity).

[L2]

If a holomorphic function is defined on a polydisc, then its mixed derivatives satisfy the several-variable Cauchy estimates there (Cauchy estimates for mixed derivatives on a polydisc).

[L3]

The boundary-radius inequality r<δΩ(K) means that Δr(a)Ω for every aK (The equal-radius polydisc boundary function).

Proof

technique · direct
1.1

By [L3], every closed polydisc Δr(a) with aK lies in Ω. Since K is compact, the union Kr is bounded and closed in Cm, hence compact, and it lies in Ω. Thus KrΩ.

L3given
1.2

Fix aK. Because Δr(a)Ω, the function f is holomorphic on Δr(a), so [L2] gives αf(a)α!r(α1++αm)supzΔr(a)f(z)α!r(α1++αm)supzKrf(z). Therefore the holomorphic function αf is bounded on K by the displayed constant.

L2given
2.1

The function αf is holomorphic on Ω, so [L1] propagates the step-1.2 bound from K to K^Ω. This is exactly the stated estimate.

L1step 1.2

Depends on

Used by

Dependency tree · two levels

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