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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Chacon tower height correlations obstruct mixing

Statement

Assume AC. For the fixed set A=L1,0=[0,2/9) and every r≥1, μ(A∩T−hrA)≥2/27>4/81=μ(A)2. Consequently Chacon is not strongly mixing. More generally, every measurable E⊆[0,1) satisfies lim inf⁡r→∞μ(E∩T−hrE)≥μ(E)/3.

Facts & Assumptions

[F1]

The next Chacon tower stacks left thirds, middle thirds, one spacer and right thirds in that order, with hr=(3r+1−1)/2 Chacon three cut one spacer towers.

[F2]

The limiting probability transformation agrees with finite tower arrows off a fixed null set Chacon partial maps extend to an invertible map mod null sets.

[F3]

Every measurable set has tower-level-union approximants with symmetric-difference error tending to zero Chacon levels approximate measurable sets.

[F4]

Strong mixing requires convergence of every fixed set-pair correlation to the product of the measures Strong and weak mixing on a probability space.

[F5]

Proof

Given: The normalized Chacon towers and their transformation under AC.

1.1F1F2F5

If Q is any union of levels at stage r, let Q(0) be the union of their left thirds. These disjoint thirds have total measure μ(Q)/3. F1's ordering and F2 show ThrQ(0) is the union of the corresponding middle thirds, modulo the fixed null set. Both unions lie in Q, so Q(0)⊆Q∩T−hrQ modulo null sets, and μ(Q∩T−hrQ)≥μ(Q)/3.

2.1F1F4step 1.1

The stage-one base is the left third of [0,2/3), hence A=[0,2/9) with measure 2/9. At every later stage it is exactly the union of all its descendant levels, since each old level partitions into three retained thirds. Step 1.1 gives the bound μ(A)/3=2/27 for every r≥1. But μ(A)2=4/81 and 2/27−4/81=2/81>0. The heights hr→∞ by F1. Thus this one fixed pair (A,A) fails F4's limit, proving failure of strong mixing.

3.1F2F3F5step 1.1∎

For measurable E, F3 gives stage-r level unions Qr with ηr=μ(E△Qr)→0. The symmetric difference of E∩T−hrE and Qr∩T−hrQr lies in (E△Qr)∪T−hr(E△Qr). Measure preservation bounds its measure by 2ηr, while μ(Qr)≥μ(E)−ηr. Step 1.1 therefore yields μ(E∩T−hrE)≥μ(E)/3−(7/3)ηr. Taking the liminf proves the general assertion. AC is inherited from F1–F3 and permits the countable choice of approximants; the estimate remains valid for null or conull E without division.

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Sources