Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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The common-support likelihood ratio is measurable

Statement

Let p0,p1:X→[0,∞) be finite-valued measurable functions on a measurable space (X,A). Define R(x)={p1(x)/p0(x),p0(x)>0,0,p0(x)=0. Then R is finite-valued, nonnegative, and measurable.

Facts & Assumptions

Given: Finite-valued nonnegative measurable functions p0,p1.

[F1]

Likelihood densities: the selected density representatives are finite-valued, nonnegative, and measurable.

[F2]

A measurable function between measurable spaces: inverse images of Borel sets under a measurable function are measurable.

[F3]

Threshold characterisations of real-valued and extended-real-valued measurability: a real-valued function is measurable if all of its strict superlevel sets are measurable.

[F4]

Arithmetic and lattice operations preserve measurability whenever they are defined: the product of two finite real-valued measurable functions is measurable.

Proof

technique · direct
1.1F1F2F3given

Define h(x)=1/p0(x) when p0(x)>0 and h(x)=0 when p0(x)=0. It is finite and nonnegative. For t<0, {h>t}=X; for t=0, {h>t}={p0>0}; for t>0, {h>t}={0<p0<1/t}. Each set is measurable by [F1] and [F2], so [F3] makes h measurable.

2.1F1F4step 1.1algebra∎

By [F1] and step 1.1, p1h is a finite nonnegative measurable function by [F4]. On {p0>0} it equals p1/p0, and on {p0=0} it is zero. Hence R=p1h and has all the asserted properties.

Depends on

Used by

Dependency tree · two levels

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Sources