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Bounded multipliers on compact self-adjoint eigenspaces define bounded operators

Statement

Assume Countable Choice. Let F∈{R,C}, H be an F-Hilbert space, and let S:H→H be compact and self-adjoint. Let Σ be its set of nonzero eigenvalues, Et=ker⁡(S−tI), Pt the orthogonal projection onto Et, and P0 the orthogonal projection onto ker⁡S. If q:{0}∪Σ→F is bounded, then for every x∈H the finite-subset net q(0)P0x+∑t∈Fq(t)Ptx,F⊆Σ finite, converges in norm to a vector Qqx. The map Qq:H→H is bounded and linear, with ∥Qq∥≤sup⁡t∈{0}∪Σ∣q(t)∣.

Facts & Assumptions

Given: Countable Choice, a real or complex Hilbert space H, a compact self-adjoint S, its set Σ of nonzero eigenvalues, their eigenspaces Et, the orthogonal projections Pt onto those spaces, and the orthogonal projection P0 onto ker⁡S.

[A1]

The Axiom of Countable Choice (ACω): Countable Choice is the choice assumption in the compact self-adjoint spectral theorem; full Choice is not needed here.

[F1]

Spectral theorem for compact self adjoint operators: The nonzero eigenspaces are mutually orthogonal, Σ is at most countable, and H=span⁡‾{Et:t∈Σ}⊕ker⁡S.

[F2]

Orthogonal decomposition by a closed subspace: A closed subspace and its orthogonal complement give a unique orthogonal decomposition.

[F3]

Orthogonality and the orthogonal complement: Distinct vectors in orthogonal eigenspaces have zero inner product.

[F4]

The induced length is a norm: ∥z∥2=⟨z,z⟩.

[F6]

The operator norm as the least bound and as the unit-sphere or unit-ball supremum: The operator norm is the supremum of ∥Tz∥ over ∥z∥≤1.

[F7]

Square-summable families on an arbitrary index set and the space ℓ2(I): For a nonnegative family, its sum is the supremum of its finite subsums; if this sum is finite, tails outside a suitable finite set have arbitrarily small sum.

[F8]

The Cauchy-sequence reals have the least-upper-bound property: Every nonempty bounded-above set of real numbers has a supremum.

Proof

1.1A1F1F2F3F4

Write x=P0x+m with m∈(ker⁡S)⊥ using [F1]–[F2]. For a finite F⊆Σ, the vectors Ptx are mutually orthogonal by [F1] and [F3]; their sum is the orthogonal projection of m onto the finite orthogonal sum of the spaces Et. Pythagoras therefore gives ∑t∈F∥Ptx∥2≤∥m∥2≤∥x∥2.

2.1F1F2F4F7F8step 1.1algebra

The set {∣q(t)∣:t∈{0}∪Σ} is nonempty and bounded, so [F8] gives its finite supremum Mq. For finite F⊆Σ, orthogonality and step 1.1 give ∥∑t∈Fq(t)Ptx∥2=∑t∈F∣q(t)∣2∥Ptx∥2≤Mq2∥x∥2. Put at=∥Ptx∥2. Step 1.1 bounds every finite subsum of (at) by ∥x∥2, so [F7] gives a finite sum with tails arbitrarily small. If Mq=0, every weighted spectral term vanishes. Otherwise, for any ε>0, choose a finite F0⊆Σ with ∑t∉F0at<(ε/Mq)2. For finite F,H⊇F0, orthogonality gives ∥∑t∈Fq(t)Ptx−∑t∈Hq(t)Ptx∥2≤Mq2∑t∈F△Hat<ε2. Thus the finite-subset net is Cauchy; completeness of H makes it norm-convergent.

3.1F4F5F6F7step 2.1algebra∎

Finite partial sums are linear in x, so taking their norm limits shows that x↦q(0)P0x+∑t∈Σq(t)Ptx is linear. Orthogonality and convergence of the finite-subset net give ∥Qqx∥2=∣q(0)∣2∥P0x∥2+∑t∈Σ∣q(t)∣2∥Ptx∥2≤Mq2∥x∥2, with the nonnegative sum understood as in [F7]. Thus Qq is bounded and [F6] gives ∥Qq∥≤Mq.

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