Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Complementation sends a disjoint ϵ-regular pair of density d to one of density 1−d

Statement

Let X,Y be disjoint nonempty vertex sets. If (X,Y) is ϵ-regular of density d in G, then it is ϵ-regular of density 1−d in G‾.

Facts & Assumptions

Given: Disjoint nonempty sets X,Y forming an ϵ-regular pair of density d in G.

[L1]

Regularity means that every sufficiently large subpair (A,B) has density within ϵ of d(X,Y) (ϵ-regular pairs and self-regular vertex sets).

[L2]

In the complement, exactly the missing pairs of distinct vertices are edges (Graph isomorphisms, automorphisms and graph complements).

Proof

technique · direct
1.1givenL2

Because X and Y are disjoint, every ordered pair in A×B consists of distinct vertices and is an edge in exactly one of G,G‾; hence dG‾(A,B)=1−dG(A,B) for every nonempty A⊆X, B⊆Y.

2.1step 1.1

Taking A=X,B=Y gives dG‾(X,Y)=1−d.

3.1step 1.1step 2.1L1∎

For every subpair meeting the thresholds in [L1], ∣dG‾(A,B)−(1−d)∣=∣dG(A,B)−d∣≤ϵ, so the complemented pair is ϵ-regular.

Disjointness is essential for the exact density formula. When X and Y overlap, diagonal pairs are edges in neither graph and contribute a correction of ∣X∩Y∣/(∣X∣∣Y∣).

Depends on

Used by

Dependency tree · two levels

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Sources