Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Induced counting lemma: regular edge and nonedge pairs force many induced copies

Statement

Let H be a graph on labelled vertices [h] and let 0<η<1/2. There are γ=γ(H,η)>0, c=c(H,η)>0, and N=N(H,η) such that the following holds. Let W1,,Wh be vertex sets of size at least N, with repetitions allowed. Assume every (Wi,Wj), including those with Wi=Wj, is γ-regular. If d(Wi,Wj)ηfor ijE(H),d(Wi,Wj)1ηfor ijE(H), then there are at least ciWi injective maps ϕ with ϕ(i)Wi that induce H.

Facts & Assumptions

Given: H,η and regular host sets as in the Statement.

[L1]

Regular dense pairs support a greedy count of many part-respecting injective edge-preserving maps of any fixed graph (Counting lemma: regular dense pairs contain many part-respecting copies of every fixed graph).

[L2]

For disjoint sets, complementation preserves the regularity parameter and replaces density d by 1d (Complementation sends a disjoint ϵ-regular pair of density d to one of density 1d).

[L3]

An induced embedding is injective and preserves both adjacency and nonadjacency; its labelled count is indH(G) (Induced embeddings and induced copies of a graph, The induced-embedding count indH(G)).

Proof

technique · direct
1.1

Colour each unordered pair ij of pattern vertices by whether it is an edge or a nonedge of H. On an edge pair retain adjacency in the host; on a nonedge pair regard nonadjacency as the required relation.

givenL3
2.1

If Wi and Wj are disjoint, [L2] turns the latter relation into a γ-regular pair of complementary density at least η. If the host sets coincide or overlap, the same conclusion for candidate degrees follows directly from the defining regularity inequalities: replace each density d(A,B) by the proportion of distinct ordered pairs in A×B that are nonedges. For candidate sets AWi and BWj the coinciding pairs number AB, so this replacement changes the proportion by at most AB/(AB)1/max(A,B) — a bound in the current candidate sizes, not in miniWi, since candidate sets shrink as the greedy argument proceeds.

step 1.1L2algebra
3.1

Choose γ small enough for the greedy argument underlying [L1] with density threshold η/2 and all (h2) coloured constraints, and let ρ=ρ(H,η)>0 be the fraction of its host set that every candidate set provably retains throughout that argument, so that every candidate set met in step 2.1 has size at least ρN. Choose N large enough that 1/(ρN)<η/4; then the diagonal error of step 2.1 stays below η/4 at every stage.

step 2.1L1choose
4.1

Run that greedy proof with the required relation for each pair. At each stage the typical-degree exclusions occupy only a controlled fraction of the current candidate set, so at least c0iWi relation-preserving maps remain for a constant c0=c0(H,η)>0.

step 3.1L1induction
5.1

At most (h2)N1iWi of these maps have a collision. Enlarge N so this is below c0iWi/2 and put c=c0/2.

step 4.1algebrachoose
6.1

Every surviving map is injective and realizes adjacency exactly on the edges of H, so it is an induced embedding by [L3]. This proves the claimed bound.

step 1.1step 5.1L3

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 32 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources