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Induced counting lemma: regular edge and nonedge pairs force many induced copies
Statement
Let be a graph on labelled vertices and let . There are , , and such that the following holds. Let be vertex sets of size at least , with repetitions allowed. Assume every , including those with , is -regular. If then there are at least injective maps with that induce .
Facts & Assumptions
Given: and regular host sets as in the Statement.
Regular dense pairs support a greedy count of many part-respecting injective edge-preserving maps of any fixed graph (Counting lemma: regular dense pairs contain many part-respecting copies of every fixed graph).
For disjoint sets, complementation preserves the regularity parameter and replaces density by (Complementation sends a disjoint -regular pair of density to one of density ).
An induced embedding is injective and preserves both adjacency and nonadjacency; its labelled count is (Induced embeddings and induced copies of a graph, The induced-embedding count ).
Proof
Colour each unordered pair of pattern vertices by whether it is an edge or a nonedge of . On an edge pair retain adjacency in the host; on a nonedge pair regard nonadjacency as the required relation.
If and are disjoint, [L2] turns the latter relation into a -regular pair of complementary density at least . If the host sets coincide or overlap, the same conclusion for candidate degrees follows directly from the defining regularity inequalities: replace each density by the proportion of distinct ordered pairs in that are nonedges. For candidate sets and the coinciding pairs number , so this replacement changes the proportion by at most — a bound in the current candidate sizes, not in , since candidate sets shrink as the greedy argument proceeds.
Choose small enough for the greedy argument underlying [L1] with density threshold and all coloured constraints, and let be the fraction of its host set that every candidate set provably retains throughout that argument, so that every candidate set met in step 2.1 has size at least . Choose large enough that ; then the diagonal error of step 2.1 stays below at every stage.
Run that greedy proof with the required relation for each pair. At each stage the typical-degree exclusions occupy only a controlled fraction of the current candidate set, so at least relation-preserving maps remain for a constant .
At most of these maps have a collision. Enlarge so this is below and put .
Every surviving map is injective and realizes adjacency exactly on the edges of , so it is an induced embedding by [L3]. This proves the claimed bound.
Depends on
Used by
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 32 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- Y. Zhao, Graph Theory and Additive Combinatorics, Theorem 2.6.2 with Remark 2.6.3(b) (standard reference, not scraped)
- D. Conlon and J. Fox, Graph removal lemmas, sec. 2.3 (standard reference, not scraped)