Alphabeta Math
LemmaStatement: Literature-sourcedProof: Literature-sourcedjudge pass (gpt-5.6-terra)audited 2026-09-04
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

At a critical point, the intrinsic Hessian agrees with the Levi-Civita Hessian

Statement

Let f:M→R be smooth, let p be a critical point of f, and let g be any Riemannian metric on M. If ∇ is the Levi-Civita connection of g, then

(∇2f)p=Hess⁡p(f).

Facts & Assumptions

Given: A smooth function f:M→R, a critical point p, a Riemannian metric g, and its Levi-Civita connection ∇.

[F1]

The intrinsic critical-point Hessian is the bilinear form represented in a chart by the second partial derivatives of the coordinate representative (The intrinsic Hessian of a smooth function at a critical point).

[F2]

The covariant Hessian satisfies (∇2f)ij=∂2(f∘x−1)∂xi∂xj−∑kΓijk∂(f∘x−1)∂xk in any chart (Riemannian metrics, symmetric cotangent-bundle connections, and covariant Hessians).

[L1]

In a chart x=(x1,…,xn) around p, dfp=∑i∂(f∘x−1)∂xi(x(p)) dxpi. (Coordinate formula for the differential of a function)

Proof

technique · coordinate computation
1.1F2given

Choose a smooth chart x around p, put a:=x(p) and h:=f∘x−1. By [F2], the coordinate matrix of (∇2f)p is (∂ijh(a)−∑kΓijk(a)∂kh(a))ij.

1.2L1givenalgebra

Since p is critical, dfp=0, and [L1] therefore forces every coefficient ∂kh(a) to vanish.

2.1F1step 1.1step 1.2∎

Step 1.1 reduces to the matrix (∂ijh(a))ij, which is exactly the matrix of Hess⁡p(f) by [F1]. Therefore (∇2f)p=Hess⁡p(f).

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources