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LemmaStatement: Literature-sourcedProof: Literature-sourcedjudge pass (gpt-5.6-terra)audited 2026-09-04
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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At a critical point, the intrinsic Hessian agrees with the Levi-Civita Hessian

Statement

Let f:MR be smooth, let p be a critical point of f, and let g be any Riemannian metric on M. If is the Levi-Civita connection of g, then

(2f)p=Hessp(f).

Facts & Assumptions

Given: A smooth function f:MR, a critical point p, a Riemannian metric g, and its Levi-Civita connection .

[F1]

The intrinsic critical-point Hessian is the bilinear form represented in a chart by the second partial derivatives of the coordinate representative (The intrinsic Hessian of a smooth function at a critical point).

[F2]

The covariant Hessian satisfies (2f)ij=2(fx1)xixjkΓijk(fx1)xk in any chart (Riemannian metrics, symmetric cotangent-bundle connections, and covariant Hessians).

[L1]

In a chart x=(x1,,xn) around p, dfp=i(fx1)xi(x(p))dxpi. (Coordinate formula for the differential of a function)

Proof

technique · coordinate computation
1.1

Choose a smooth chart x around p, put a:=x(p) and h:=fx1. By [F2], the coordinate matrix of (2f)p is (ijh(a)kΓijk(a)kh(a))ij.

F2given
1.2

Since p is critical, dfp=0, and [L1] therefore forces every coefficient kh(a) to vanish.

L1givenalgebra
2.1

Step 1.1 reduces to the matrix (ijh(a))ij, which is exactly the matrix of Hessp(f) by [F1]. Therefore (2f)p=Hessp(f).

F1step 1.1step 1.2

Depends on

Used by

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Dependency tree · two levels

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Sources