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Local approximation by the face-average Crouzeix–Raviart interpolant

Statement

Assume Countable Choice and the setup of The face-average Crouzeix–Raviart interpolant, a shape-regular affine mesh, and 1/2<r≤1. The face-average interpolant is defined for every u∈H1+r(K) by the traces of Fractional face traces and cellwise Green identity on a simplex and reproduces P1(K). Uniformly over all cells, ∥∇(u−IKCRu)∥L2(K)≤ChKr∣u∣H1+r(K),∥u−IKCRu∥L2(K)≤ChK1+r∣u∣H1+r(K). For each facet F⊂∂K, hF−1/2∥γF(u−IKCRu)∥L2(F)≤ChKr∣u∣H1+r(K). If u∈H01(Ω), then the global interpolant has matching interior face means and zero boundary face means, so IhCRu∈VhCR,0.

Facts & Assumptions

Given: Countable Choice, a shape-regular affine simplex, the local and global face-average interpolants, and the Slobodeckij regularity convention of Fractional Sobolev regularity on a simplex.

[A1]

Countable Choice is required by the simplex trace, reference Poincare, and affine shape-scaling suppliers. (The Axiom of Countable Choice (ACω))

For a cell or face E of positive measure, write avg⁡Ef:=∣E∣−1∫Ef.

[F1]

The face mean of a continuous affine polynomial is its value at the face barycenter, and the face-average interpolant reproduces every affine polynomial. (Face averages are unisolvent for the local Crouzeix–Raviart element)

[F2]

Face traces on a simplex are bounded on H1; for 1/2<r<1 they satisfy the face-mean estimate in the preceding item. (Fractional face traces and cellwise Green identity on a simplex)

[F3]

The mean-zero Poincare–Wirtinger inequality holds on the reference simplex. (Poincare–Wirtinger inequality on a reference simplex)

[F4]

Shape regularity gives ∥AK∥≍hK, ∥AK−1∥≍hK−1, ∣K∣≍hKd, and ∣F∣≍hKd−1. (Shape regularity controls affine simplex geometry)

Proof

1.1A1F2given

On the reference simplex, each face mean of v∈H1 is bounded by C∥v∥H1 by [F2]. The interpolant is a finite sum of these means times fixed affine shape polynomials, so it is bounded from H1 to H1. The trace-defined formula of The face-average Crouzeix–Raviart interpolant is therefore continuous on H1+r⊂H1.

2.1A1F3givenstep 1.1

First work on the reference simplex. Choose an affine polynomial p with ∇p=avg⁡K∇u and avg⁡K(u−p)=0. For 1/2<r<1, applying the fractional Poincare estimate proved in step 1.1 of Fractional face traces and cellwise Green identity on a simplex to each component of ∇u gives ∥∇(u−p)∥L2(K)≤C∣u∣H1+r(K). The mean-zero Poincare–Wirtinger inequality [F3] then gives ∥u−p∥L2(K)≤C∥∇(u−p)∥L2(K). At r=1, apply [F3] to the mean-zero first derivatives, then again to u−p, obtaining ∥u−p∥H1(K)≤C∣u∣H2(K).

3.1A1F1F2F4step 1.1step 2.1algebra

Since p is affine, reproduction [F1] gives u−IKCRu=(u−p)−IKCR(u−p). The reference stability from step 1.1 and the estimates of step 2.1 bound the reference H1 error by C∣u∣H1+r. Under the affine map FK(x^)=bK+AKx^, each face surface Jacobian is constant, so face averages and the interpolant commute with pullback. The fractional gradient seminorm obeys ∣u^∣H1+r(K^)≤ChK1+r−d/2∣u∣H1+r(K): substitute x=FK(x^) in the double integral, use ∣AKz∣≍hK∣z∣ and ∣det⁡AK∣≍hKd from [F4], and include the factor AKT in the pulled-back gradient. The physical gradient and L2 error scaling factors are respectively hKd/2−1 and hKd/2, yielding the two stated powers.

4.1A1F2step 3.1givenalgebra∎

Apply the scaled H1 trace bound [F2] to e=u−IKCRu: hF−1/2∥e∥L2(F)≤C(hK−1∥e∥L2(K)+∥∇e∥L2(K)). Substituting step 3.1 gives the stated face estimate. On an interior facet, both adjacent restrictions of u have the same Sobolev trace because u∈H1(Ω); on a boundary facet the trace of u∈H01(Ω) is zero. The global interpolant therefore has matching interior face means and zero boundary means.

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