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The rank-one DAHA difference-reflection operators satisfy the presentation

Statement

Let P=K[z,z−1]. Define operators on P by

(Πf)(z)=f(q−1z−1),(σ1f)(z)=f(z−1),(σ0f)(z)=f(q−2z−1), (Tif)(z)=t(σif)(z)+(t−t−1)(σif)(z)−f(z)ui(z)−1,u1(z)=z−2,u0(z)=q2z2.

Then Z↦Mz, Z−1↦Mz−1, π↦Π, and Ti↦Ti satisfy every defining relation of The equal-parameter double-affine Hecke algebra of type A1. Consequently they define a unital representation of Hq,t(A1) on P.

Facts & Assumptions

Given: K=Q(q,t), the rank-one substitutions and Bernstein polynomials, and the DAHA quotient presentation.

[F1]

The rank-one root datum and parameter conventions for DAHA: s1(zm)=z−m, s0(zm)=q−2mz−m, π(zm)=q−mz−m, and u1=z−2, u0=q2z2.

[F2]

The equal-parameter double-affine Hecke algebra of type A1: the required relations are the Laurent inverse, the π-relations, the quadratic relations, and the Bernstein cross-relations for all m∈Z.

[F3]

The rank-one DAHA Bernstein quotients are Laurent polynomials: (zm−si(zm))/(1−ui(z))=Bi,m(z)∈K[z,z−1] for both affine simple roots and every integer m.

[F4]

The free associative R-algebra on a set and descent of relations: an assignment of the free generators to an associative K-algebra that kills all defining relators descends uniquely to a homomorphism from the presented quotient.

[F5]

The rank-one DAHA polynomial representation: the candidate generator assignment sends Z to Mz, Z−1 to Mz−1, π to the stated substitution, and Ti to the displayed difference-reflection operators; the relation checks below establish that it is an algebra action.

Proof

1.1F1F2givenalgebra

Multiplication by z and z−1 are inverse operators, so the Laurent-inverse relator holds. Direct substitution gives Π2=1 and ΠMzΠ=Mq−1z−1, which is the πZπ relation. It also gives Πσ0Π=σ1 and ΠMu0Π=Mu1; since both Hecke formulas use the same t, conjugating the formula for T0 yields ΠT0Π=T1.

1.2F1F2algebra

Put c=t−t−1, ai=(tui−t−1)/(ui−1), and bi=−c/(ui−1). Since σi(ui)=ui−1, one has Ti=aiσi+bi, σi(ai)=(t−1ui−t)/(ui−1), and σi(bi)=cui/(ui−1). Multiplication in the crossed-product operator algebra gives aiσi(bi)+biai=cai and aiσi(ai)+bi2=1+cbi, so Ti2=cTi+1, equivalent to (Ti−t)(Ti+t−1)=0.

1.3F2F3algebra

For multiplication Mf by a Laurent polynomial, direct expansion of TiMf−Msi(f)Ti gives multiplication by c(f−si(f))/(1−ui). With f=zm, [F3] identifies this Laurent polynomial with cBi,m, which is exactly each Bernstein relation in [F2]. The finite-sum formulas in [F3] also show that Ti preserves P.

2.1step 1.1step 1.2step 1.3F2F4F5algebra∎

The assignments in [F5], checked in steps 1.1, 1.2, and 1.3, satisfy all relators of the free-algebra quotient. By [F4] they descend to a unital K-algebra homomorphism Hq,t(A1)→End⁡K(P).

Depends on

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Nothing in the library uses this result yet.

Cited to discharge well-definedness by The rank-one DAHA polynomial representation.

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