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The diagonal heat semigroup has the stated generator domain

Statement

Let H, A, and Et be as in Diagonal Dirichlet sine-mode heat model with constant forcing. The maps Et for t≥0 satisfy E0=I and Et+s=EtEs, are contractions in ℓ2, and are strongly continuous at t=0. Define the generator domain to consist of those u∈H for which the right limit lim⁡t↓0Etu−ut exists in H. This domain is exactly D(A)={u:∑k≥1k4∣uk∣2<∞}, and the limit equals Au=(−k2uk)k≥1.

Facts & Assumptions

Given: The sequence space, diagonal operator, and maps in the Statement.

[F1]

Diagonal Dirichlet sine-mode heat model with constant forcing and Square-summable families on an arbitrary index set and the space ℓ2(I): H consists of real families u=(uk)k≥1 with ∑k≥1∣uk∣2<∞, and (Etu)k=exp⁡(−k2t)uk for every k≥1.

[F2]

The exponential addition formula exp⁡(x+y)=exp⁡(x)exp⁡(y): exp⁡(x+y)=exp⁡(x)exp⁡(y) and exp⁡(0)=1.

[F3]

The exponential is positive and satisfies exp⁡(−x)=1/exp⁡(x) and The exponential function is strictly increasing: exp⁡(x)>0, and x≤y implies exp⁡(x)≤exp⁡(y).

Proof

1.1F1F2F3algebra

Coordinatewise, [F2] gives exp⁡(−k2(t+s))=exp⁡(−k2t)exp⁡(−k2s) and E0u=u, so Et+s=EtEs. If t≥0, [F3] gives 0<exp⁡(−k2t)≤1; hence ∑k∣(Etu)k∣2≤∑k∣uk∣2, proving that Et maps H to itself and is a contraction.

1.2F1F3F4algebra

At x=0 the bound 0≤1−exp⁡(−x)≤x is equality; for x>0, [F4] applied to s↦exp⁡(−s) on [0,x] gives 1−exp⁡(−x)=xexp⁡(−ξ) for some ξ∈(0,x), and [F3] bounds exp⁡(−ξ) by 1. Thus the bound holds for all x≥0. For u∈D(A), the kth coordinate of (Etu−u)/t tends to −k2uk by the chain rule and exponential derivative in [F4]. Its difference from that limit has absolute value at most 2k2∣uk∣, by the same bound. The squared tail of these differences is therefore at most 4∑k>Kk4∣uk∣2, which tends to zero; on every finite head the coordinate limits give norm convergence. Hence the right limit exists in H and equals Au.

2.1F1F3F4step 1.1algebrachoose

Fix u∈H and ε>0. By convergence of its square sum, choose K so that ∑k>K∣uk∣2<ε2/4. The squared norm of the tail of Etu−u is at most this tail because ∣exp⁡(−k2t)−1∣≤1 by [F3]; for the finitely many indices k≤K, continuity of the exponential at zero from [F4] makes their squared sum less than ε2/4 for all sufficiently small t>0. Thus ∥Etu−u∥2<ε, proving strong continuity at zero.

3.1F1F4step 1.2algebra∎

Conversely, suppose (Etu−u)/t converges in H to v. For each k, coordinate evaluation is continuous since ∣wk∣≤∥w∥2; therefore its limit is vk=−k2uk, using [F4]. Since v∈H, ∑kk4∣uk∣2=∑k∣vk∣2<∞, so u∈D(A). Together with step 1.2 this identifies the generator domain and its value.

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