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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Dihedral Fox coloring counts are preserved by Reidemeister moves

Statement

Let p be an odd prime. A Fox p-coloring of a finite regular oriented link diagram D assigns an element of Fp to each arc and satisfies 2xo=xi+xj at every crossing, where xo is the overarc color and xi,xj are the two underarc colors. If D′ is obtained from D by planar isotopy or one oriented Reidemeister move of type R1, R2, or R3, restriction outside the move disk gives a bijection from the Fox p-colorings of D to those of D′. Consequently the number of Fox p-colorings is unchanged along every finite sequence of such moves. The local bijections use no choice principle.

Facts & Assumptions

Given: An odd prime p and a finite regular oriented link diagram D changed to D′ by one planar isotopy or one oriented R1, R2, or R3 move.

[F1]

Quandles and knot-diagram colorings: a quandle coloring assigns one element to each arc and at a crossing the target underarc color is the source underarc color acted on by the overarc color.

[F2]

The dihedral operation is a quandle: on Fp, the operation is a∗b=2b−a; each right translation is an involution, and (a∗b)∗c=(a∗c)∗(b∗c).

[F3]

Oriented Reidemeister moves: each local move is supported in a disk, all strand orientation/sign variants are included, and a planar isotopy transports the diagram and its decorations.

Proof

1.1F2algebra

For fixed b∈Fp, define Rb(a)=a∗b=2b−a. Then Rb(Rb(a))=2b−(2b−a)=a, so Rb−1=Rb. Also a∗a=2a−a=a. Thus both the forward and reverse crossing rules use the same involution, and an arc's color is uniquely recoverable across one underpass.

2.1F1F2F3step 1.1algebra

In an R1 disk, the coloring relation on the kinked side is either y=x∗x or x=y∗x, where x is the unchanged boundary color and y is the color of the new interior underarc. In the first case y=x by idempotency; in the second, Rx(y)=x has the unique solution y=Rx(x)=x because Rx is bijective. Deleting the kink is the inverse restriction map. The two formulas cover both strand directions because the inverse operation equals the operation by step 1.1.

2.2F1F2F3step 1.1algebra

In an R2 disk, fix the color b of the strand passing over the other strand and the incoming underarc color a. The first crossing changes the underarc color to Rb(a), and the second changes it by Rb−1; their composition is Rb−1(Rb(a))=a. Therefore every boundary coloring extends uniquely across the two-crossing side, and the reverse R2 move gives the inverse bijection. Other orientation variants replace one of these maps by its inverse, which is the same map by step 1.1.

2.3F1F2F3step 1.1algebra

For a braid-like R3 orientation, start with boundary colors a,b,c. Propagating through the two sides gives respectively (c,b∗c,(a∗b)∗c) and (c,b∗c,(a∗c)∗(b∗c)). The last coordinates agree by right self-distributivity in [F2], so every boundary coloring on either side has a unique matching extension on the other. Reversing a crossing replaces a right translation by its inverse; step 1.1 makes that the same map, and relabeling the three strands gives every height-order and orientation variant in [F3].

3.1F1F3step 2.1step 2.2step 2.3construct∎

If D is empty, its unique empty coloring is carried to itself by planar isotopy, and no Reidemeister move is supported on the empty diagram. If D is nonempty, planar isotopy carries every arc and local crossing relation bijectively to its image, while steps 2.1, 2.2, and 2.3 give explicit coloring bijections for every local move. Composing the finitely many bijections along any finite move sequence preserves the coloring count. These constructions act on finite arc labels and use no choice principle.

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