Alphabeta Math
LemmaStatement: Literature-sourcedProof: Literature-sourcedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-27
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Distinguished-subset identities

Statement

Let R be a commutative ring and let f,g∈R. Then D(0)=∅,D(1)=Spec⁡(R),D(fg)=D(f)∩D(g). Moreover, for every integer n≥1 one has D(fn)=D(f).

Facts & Assumptions

Given: A commutative ring R, elements f,g∈R, and an integer n≥1.

[L1]

D(h) is the set of prime ideals that do not contain h (Principal distinguished subsets of the prime spectrum).

Proof

technique · direct
1.1L1given

Every prime ideal contains 0, so no prime lies in D(0). Every prime ideal is proper, so it does not contain 1; hence every prime lies in D(1). Therefore D(0)=∅ and D(1)=Spec⁡(R).

1.2L1givenalgebra

Let p∈Spec⁡(R). Then p∈D(fg) exactly when fg∉p. Because p is prime, this is equivalent to saying that neither f nor g lies in p, that is, p∈D(f)∩D(g). The same prime-ideal property shows that fn∈p exactly when f∈p, so D(fn)=D(f).

2.1step 1.1step 1.2∎

Steps 1.1 and 1.2 prove the stated identities for principal distinguished subsets.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources