Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Doubling variables: existence, relative contacts at the maximiser and localisation

Statement

Let n≥1, T>0, let u:Rn×[0,T]→R be bounded above and upper semicontinuous, and let v:Rn×[0,T]→R be bounded below and lower semicontinuous. Fix α,ρ>0 and define Φ(x,y,t,s):=u(x,t)−v(y,s)−α2∣x−y∣2−α2∣t−s∣2−ρ (∣x∣2+∣y∣2) on Rn×Rn×[0,T]2, with Mα,ρ:=sup⁡Φ. Then: (1) Mα,ρ is finite and attained, and at every maximiser (xα,yα,tα,sα) the C1 test functions ψ1(x,t):=α2∣x−yα∣2+α2∣t−sα∣2+ρ∣x∣2,ψ2(y,s):=−α2∣xα−y∣2−α2∣tα−s∣2−ρ∣y∣2 satisfy: u−ψ1 has a local maximum at (xα,tα) and v−ψ2 has a local minimum at (yα,sα), with pα:=Dxψ1(xα)=α(xα−yα)+2ρxα,qα:=Dyψ2(yα)=α(xα−yα)−2ρyα,pα0:=∂tψ1(tα)=∂sψ2(sα)=α(tα−sα); (2) for each fixed ρ>0, along any sequence of maximisers as α→∞, α(∣xα−yα∣2+∣tα−sα∣2)⟶0,(1+∣pα∣)(∣xα−yα∣+∣tα−sα∣)⟶0,∣xα−yα∣+∣tα−sα∣⟶0, while ∣qα−pα∣=2ρ∣xα+yα∣ is bounded by 2ρ(∣xα∣+∣yα∣) and is not claimed to vanish for fixed ρ; (3) at every maximiser α2(∣xα−yα∣2+∣tα−sα∣2)+ρ(∣xα∣2+∣yα∣2)≤sup⁡u−inf⁡v−Mα,ρ, so whenever the maximiser values Mα,ρ are bounded below by m on a set of parameters, the corresponding maximisers satisfy ρ(∣xα∣2+∣yα∣2)≤sup⁡u−inf⁡v−m and ∣qα−pα∣≤2(2ρ(sup⁡u−inf⁡v−m))1/2. No choice principle is used.

Facts & Assumptions

Given: Bounded-above upper semicontinuous u and bounded-below lower semicontinuous v on Rn×[0,T], parameters α,ρ>0, and the function Φ of the statement.

[F1]

Upper semicontinuity of u and lower semicontinuity of v mean that every superlevel set of u and every sublevel set of v is relatively closed; equivalently, −v is upper semicontinuous (Upper and lower semicontinuity on subsets of Rn).

[F2]

Every upper semicontinuous real-valued function on a nonempty compact subset of Rn is bounded above and attains its maximum (Semicontinuous extreme value theorem on compact Euclidean sets).

[F4]

If S⊆R is nonempty, bounded above and w is an upper bound of S with the property that for every ε>0 there is s∈S with w−ε<s, then w=sup⁡S; in particular sup⁡S−ε<s for some s∈S and every ε>0 (Epsilon characterisation of the supremum).

Proof

technique · coercive weight for existence, monotonicity in $\alpha$ for the localisation, and explicit $C^1$ contacts for the two tests
1.1F1F2F3algebra

Existence and finiteness of Mα,ρ. On Rn×Rn×[0,T]2 the function Φ is upper semicontinuous, being u plus the upper semicontinuous −v plus continuous terms by [F1]; it is bounded above by sup⁡u−inf⁡v<∞ because the quadratic and weight terms are nonpositive. Pick any point p0:=(0,0,0,0) and put m0:=Φ(p0)∈R; the superlevel set S0:={Φ≥m0} is nonempty, closed by upper semicontinuity, and bounded because ρ(∣x∣2+∣y∣2)≤sup⁡u−inf⁡v−m0 on it; hence S0 is compact by [F3]. On S0 the restriction of Φ is real-valued and upper semicontinuous, so it attains a maximum by [F2]; that maximum is a global maximum of Φ because every point outside S0 has value <m0≤max⁡S0Φ. Hence Mα,ρ is finite and attained.

2.1step 1.1algebra

The relative contacts and their derivatives. Let (xα,yα,tα,sα) be a maximiser. Fixing (y,s)=(yα,sα), the inequality Φ(x,yα,t,sα)≤Φ(xα,yα,tα,sα) for all (x,t) reads u(x,t)−ψ1(x,t)≤u(xα,tα)−ψ1(xα,tα), so u−ψ1 has a local maximum at (xα,tα); fixing (x,t)=(xα,tα) similarly gives v(y,s)−ψ2(y,s)≥v(yα,sα)−ψ2(yα,sα), a local minimum of v−ψ2 at (yα,sα). The displayed gradients and time derivatives are the derivatives of the two quadratic test functions: Dxψ1=α(x−yα)+2ρx evaluated at xα gives pα, Dyψ2=α(xα−y)−2ρy evaluated at yα gives qα, and ∂tψ1=α(t−sα), ∂sψ2=α(tα−s) both equal pα0 at the maximiser.

3.1step 2.1algebra

The weight bound (3). At a maximiser, Φ(xα,yα,tα,sα)=Mα,ρ, that is u(xα,tα)−v(yα,sα)−α2dα2−ρ(∣xα∣2+∣yα∣2)=Mα,ρ; since u(xα,tα)≤sup⁡u and −v(yα,sα)≤−inf⁡v, the sum of the two penalty terms is at most sup⁡u−inf⁡v−Mα,ρ, which is (3). If in addition Mα,ρ≥m then ρ(∣xα∣2+∣yα∣2)≤sup⁡u−inf⁡v−m, and ∣qα−pα∣≤2ρ(∣xα∣+∣yα∣)≤2ρ2(∣xα∣2+∣yα∣2)≤2(2ρ(sup⁡u−inf⁡v−m))1/2.

4.1step 2.1step 3.1F4algebra

Localisation as α→∞. Fix any sequence αj→∞ and any corresponding sequence of maximisers (xj,yj,tj,sj); these are exactly the sequences quantified in part (2). For fixed ρ, α↦Mα,ρ is nonincreasing and bounded below by Φ(0,0,0,0), so it converges. Put dj2:=∣xj−yj∣2+∣tj−sj∣2. Evaluating the αj/2-function at this same maximiser gives Mαj/2,ρ≥Mαj,ρ+αj4dj2, hence αjdj2≤4(Mαj/2,ρ−Mαj,ρ)→0. In particular ∣xj−yj∣+∣tj−sj∣→0. By step 3.1, ∣xj∣ is uniformly bounded for fixed ρ. With pj=αj(xj−yj)+2ρxj, the bounds αj∣xj−yj∣(∣xj−yj∣+∣tj−sj∣)≤2αjdj2→0 and 2ρ∣xj∣(∣xj−yj∣+∣tj−sj∣)→0 give (1+∣pj∣)(∣xj−yj∣+∣tj−sj∣)→0. Finally qj−pj=−2ρ(xj+yj) and step 3.1 gives the asserted bound on ∣qj−pj∣, which need not vanish for fixed ρ. The argument applies to every given sequence of maximisers and selects none.

5.1step 1.1step 2.1step 3.1step 4.1∎

Conclusion. Part (1) is steps 1.1 and 2.1, part (2) is step 4.1, and part (3) is step 3.1; the maximiser is obtained from the compactness of a closed bounded superlevel set and the extreme-value property for upper semicontinuous functions, and no sequence, point or index is selected in the construction.

Remarks

The contacts in part (1) are relative to Rn×[0,T]. A maximiser may have tα=0 or sα=0 (for example, u(x,t)=−t, v(y,s)=s), or lie on a terminal face. The corresponding derivative belongs to the first-order superjet or subjet of Viscosity testing by first-order jets, and closure of the jet inequality only when the contact time is in (0,T), where the restricted domain is open. Viscosity inequalities in the interior therefore require a separate exclusion of time-boundary contacts.

Depends on

Used by

Dependency tree · two levels

52 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources