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Dyadic cell-average projections converge strongly in L2 of a bounded set

Statement

Assume Countable Choice. Let D⊂R3 be bounded and Lebesgue measurable, and choose a half-open cube Q of positive side length containing D. Subdivide Q into its nested dyadic cubes at mesh hN=2−Nside⁡(Q). Let EN,j=D∩QN,j range over the finitely many cells of positive measure, let VN⊂L2(D;C) be the functions constant on each such cell, and define PN by replacing a function on each EN,j by its cell average. Then PN is the orthogonal projection onto VN, ∥PN∥≤1, the spaces VN are increasing, and PNv→v in L2(D;C) for every v∈L2(D;C).

Facts & Assumptions

Given: Countable Choice, a bounded measurable D, a positive-side containing cube Q, its nested dyadic partitions, and v∈L2(D;C).

[F1]

Finite linear combinations of dyadic box indicators are dense in real L2 of the Borel cube (Base-b box step functions are dense in L2 of the cube); the complex conclusion follows by applying the real result to real and imaginary parts.

[F3]

Under Countable Choice, a function measurable for the completion is almost everywhere equal to a Borel-measurable function when the base sigma-algebra is Borel (A function measurable for a completion is almost everywhere equal to one measurable for the original sigma-algebra).

Proof

Given: Countable Choice, a bounded measurable D, a positive-side containing cube Q, its nested dyadic partitions, and v∈L2(D;C).

1.1givenF2constructalgebra

For each positive-measure cell EN,j the average is finite by Cauchy–Schwarz, since ∫EN,j∣v∣≤∣EN,j∣1/2∥v∥L2(EN,j). For every function constant on the cells, the integral of v−PNv against that function is zero cell by cell. Thus v−PNv⊥VN and PNv∈VN, so PN is the orthogonal projection. Pythagoras gives ∥PNv∥2≤∥v∥2.

1.2F1F2F3givenconstruct

Extend v by zero from D to Q. The extension is measurable for completed Lebesgue measure; rescale and translate Q to [0,1)3, which preserves completed measurability by [F2]. Apply [F3] separately to the real and imaginary parts to obtain a Borel-measurable representative of the rescaled extension equal to it almost everywhere. This representative is in Borel L2 because the original extension is square integrable and the affine change multiplies its squared integral by the fixed positive factor side⁡(Q)−3. Applying [F1] to its real and imaginary parts gives dyadic box step functions converging in Borel L2([0,1)3), hence also in completed L2. Pulling them back to Q and restricting to D preserves convergence up to the fixed affine measure factor. Every finite family of base-2 boxes is constant on the cells of a sufficiently fine common dyadic partition, so the restrictions belong to some VN. Thus ⋃NVN is dense in L2(D;C); the partitions are nested, so VN⊆VN+1.

2.1givenstep 1.1step 1.2algebra∎

Fix ε>0. By step 1.2 choose w∈Vm with ∥v−w∥2<ε/2. For every N≥m, nesting gives PNw=w. Therefore ∥PNv−v∥2≤∥PN(v−w)∥2+∥v−w∥2≤2∥v−w∥2<ε, by step 1.1. Thus PNv→v in L2(D;C).

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