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Dyadic cell-average projections converge strongly in L2 of a bounded set
Statement
Assume Countable Choice. Let be bounded and Lebesgue measurable, and choose a half-open cube of positive side length containing . Subdivide into its nested dyadic cubes at mesh . Let range over the finitely many cells of positive measure, let be the functions constant on each such cell, and define by replacing a function on each by its cell average. Then is the orthogonal projection onto , , the spaces are increasing, and in for every .
Facts & Assumptions
Given: Countable Choice, a bounded measurable , a positive-side containing cube , its nested dyadic partitions, and .
Finite linear combinations of dyadic box indicators are dense in real of the Borel cube (Base- box step functions are dense in of the cube); the complex conclusion follows by applying the real result to real and imaginary parts.
Complex Cauchy--Schwarz holds, and Lebesgue measure is invariant under translations and scales under invertible linear changes of variables (The complex pairing is well-defined and satisfies Cauchy–Schwarz, Lebesgue outer measure, Lebesgue measurability and Lebesgue measure are unchanged by translation, A linear map of sends Lebesgue measurable sets to Lebesgue measurable sets, with when is invertible and Lebesgue null when it is not, Lebesgue measurable sets, the family , and the restricted set function ).
Under Countable Choice, a function measurable for the completion is almost everywhere equal to a Borel-measurable function when the base sigma-algebra is Borel (A function measurable for a completion is almost everywhere equal to one measurable for the original sigma-algebra).
Proof
Given: Countable Choice, a bounded measurable , a positive-side containing cube , its nested dyadic partitions, and .
For each positive-measure cell the average is finite by Cauchy–Schwarz, since . For every function constant on the cells, the integral of against that function is zero cell by cell. Thus and , so is the orthogonal projection. Pythagoras gives .
Extend by zero from to . The extension is measurable for completed Lebesgue measure; rescale and translate to , which preserves completed measurability by [F2]. Apply [F3] separately to the real and imaginary parts to obtain a Borel-measurable representative of the rescaled extension equal to it almost everywhere. This representative is in Borel because the original extension is square integrable and the affine change multiplies its squared integral by the fixed positive factor . Applying [F1] to its real and imaginary parts gives dyadic box step functions converging in Borel , hence also in completed . Pulling them back to and restricting to preserves convergence up to the fixed affine measure factor. Every finite family of base-2 boxes is constant on the cells of a sufficiently fine common dyadic partition, so the restrictions belong to some . Thus is dense in ; the partitions are nested, so .
Fix . By step 1.2 choose with . For every , nesting gives . Therefore , by step 1.1. Thus in .
Depends on
- The space $L^p(\mu)$ as the quotient by null functions
- Base-$b$ box step functions are dense in $L^2$ of the cube
- A linear map $T$ of $\mathbb{R}^n$ sends Lebesgue measurable sets to Lebesgue measurable sets, with $\lambda_n(T[E])=|\det T|\,\lambda_n(E)$ when $T$ is invertible and $T[E]$ Lebesgue null when it is not
- Lebesgue outer measure, Lebesgue measurability and Lebesgue measure are unchanged by translation
- A function measurable for a completion is almost everywhere equal to one measurable for the original sigma-algebra
- The complex $L^2$ pairing is well-defined and satisfies Cauchy–Schwarz
- Lebesgue measurable sets, the family $\mathcal{L}(\mathbb{R}^n)$, and the restricted set function $\lambda_n$
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
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Sources
- Art B. Owen, Monte Carlo Variance of Scrambled Net Quadrature, §6 (standard reference, not scraped)
- Andreas Neubauer and Ronny Ramlau, Lecture Notes: Integral Equations and Boundary Value Problems (standard reference, not scraped)