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Each Feferman–Levy real layer is countable
Statement
For every , the real layer is countable in the Feferman–Levy model .
Facts & Assumptions
Given: One fixed and the corresponding layer in .
Each real layer has a ground-model cardinal bound supplies in a specified surjection .
Every finite ground aleph is countable in the Feferman–Levy model says that is countable in .
A nonempty set is at most countable iff it is a surjective image of says that every nonempty countable set is the range of a surjection from , without Choice.
Proof
The ordinal is nonempty. By F2 and F3, fix in one surjection , and form . Both factors are sets of , and ordinary ordered-pair Separation produces their composition. For each , its -preimage is nonempty, so take its least ordinal member ; then the -preimage of is a nonempty set of naturals and has a least member . Thus , so . This fixes one witness for one already fixed ; it does not choose a family indexed by .
The layer is nonempty because it contains the interpretation of the constantly-zero Boolean name. Sending each to its least -preimage gives an injection into , so is at most countable. The least-preimage clauses are definable and involve one fixed map; no choice function for the family is formed.
Depends on
Used by
Dependency tree · two levels
17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Thomas Jech, The Axiom of Choice, Lemmas 10.8–10.9 and conclusion of Theorem 10.6, printed p. 144 (standard reference, not scraped)