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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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Each Feferman–Levy real layer is countable

Statement

For every m<ω, the real layer Rm is countable in the Feferman–Levy model N.

Facts & Assumptions

Given: One fixed m<ω and the corresponding layer in N.

[F1]

Each real layer has a ground-model cardinal bound supplies in N a specified surjection em:m+1VRm.

[F2]

Every finite ground aleph is countable in the Feferman–Levy model says that m+1V is countable in N.

[F3]

A nonempty set is at most countable iff it is a surjective image of N says that every nonempty countable set is the range of a surjection from ω, without Choice.

Proof

technique · direct composition of the two supplied maps
1.1

The ordinal m+1V is nonempty. By F2 and F3, fix in N one surjection f:ωm+1V, and form gm=emf. Both factors are sets of N, and ordinary ordered-pair Separation produces their composition. For each xRm, its em-preimage is nonempty, so take its least ordinal member ξ; then the f-preimage of ξ is a nonempty set of naturals and has a least member k. Thus gm(k)=x, so gm:ωRm. This fixes one witness for one already fixed m; it does not choose a family indexed by ω.

F1F2F3construct
2.1

The layer is nonempty because it contains the interpretation of the constantly-zero Boolean name. Sending each xRm to its least gm-preimage gives an injection into ω, so Rm is at most countable. The least-preimage clauses are definable and involve one fixed map; no choice function for the family (Rm)m<ω is formed.

step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources