Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Extending a partial comparison homotopy by one degree

Statement

Let f,g:PQ be augmentation-preserving maps of projective resolutions lifting the same object morphism. Suppose h0,,hn1 have already been chosen so that fkgk=dk+1Qhk+hk1dkP holds for every k<n (with h1=0). Then there exists hn:PnQn+1 extending the homotopy identity to degree n.

Facts & Assumptions

Given: Projective resolutions PA, QB, two comparison maps f,g lifting the same object morphism, and a partial chain homotopy through degree n1.

[L1]

A chain homotopy is given by the equation fngn=dn+1Qhn+hn1dnP (A chain homotopy).

[L2]

Cycle objects are kernels of the differentials (Cycle and boundary subobjects of a complex).

[L3]

Projective objects lift across epimorphisms (Projective object).

Proof

technique · direct
1.1

Put cn:=fngnhn1dnP, with h1=0 when n=0. Using the chain-map identities for f and g and the already verified lower-degree homotopy equations, one gets dnQcn=0. Thus cn lands in Zn(Q) by [L2]; when n=0, the common augmentation condition on f0 and g0 says exactly that c0 lands in ker(εQ)=Z0(Q).

L1L2givenalgebra
2.1

Exactness of Q makes Qn+1Zn(Q) epic, and Pn is projective. By [L3], lift cn to a map hn:PnQn+1. Then dn+1Qhn=cn, which is precisely the degree-n homotopy equation from [L1].

L3step 1.1construct

Depends on

Used by

Dependency tree · two levels

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Sources