Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Projective comparison maps are unique up to chain homotopy

Statement

Assume the Axiom of Dependent Choice.

Any two augmentation-preserving maps between projective resolutions lifting the same object morphism are chain-homotopic.

Facts & Assumptions

Given: Two augmentation-preserving maps f,g:PQ between projective resolutions, lifting the same object morphism u:AB.

[L1]

A partial comparison homotopy extends one degree at a time (Extending a partial comparison homotopy by one degree).

[L2]

The maps f and g are comparison maps in the sense of Augmentation-preserving maps of projective resolutions.

[L3]

Dependent choice licenses the countable successor-by-successor selection of compatible homotopy components (The axiom of dependent choice: a relation in which every element is related to something admits an N-indexed chain).

Proof

technique · direct
1.1

Start at degree 0. Because f and g lift the same object map, [L1] produces h0:P0Q1. Every partial homotopy through degree n1 extends one degree further by [L1], and the successive choices depend on the previously chosen components. Therefore [L3] produces a family hn:PnQn+1 in every degree.

L1L2L3construct
2.1

By construction, the family (hn) satisfies the defining chain-homotopy equation in every degree. Therefore f and g are chain-homotopic.

step 1.1

Depends on

Used by

Dependency tree · two levels

18 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources