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Finite atomic sums are dense in H1

Statement

Assume Countable Choice. The finite linear combinations of H1 atoms are dense in H1(Rn): for every f∈H1(Rn) and every ε>0 there are finitely many atoms a1,…,aN and coefficients λ1,…,λN with ∥f−∑1≤j≤Nλjaj∥H1<ε.

Facts & Assumptions

Given: Countable Choice, f∈H1(Rn) and ε>0, with the (1,∞,0)-atoms of Hp atoms with a prescribed moment order and the H1 functional of The real Hardy space Hp defined by a radial maximal function.

[F1]

The atomic characterisation of H1 gives a sequence (λj)∈ℓ1 and (1,∞,0)-atoms aj, reindexed by j≥1, with f=∑jλjaj converging in S′, with ∑j∣λj∣≤C∥f∥H1 for a suitable constant; moreover every such series converges also in the H1 quasi-norm, which for p=1 is the norm ∥⋅∥H1 (Atomic characterisation of real Hp for 0<p≤1, The real Hardy space Hp defined by a radial maximal function).

[F2]

For an ℓ1 sum of atoms indexed by j≥1, the partial sums converge to the sum in the H1 quasi-norm and the tail bound ∥g−∑1≤j≤Nλjaj∥H1≤C(∑j>N∣λj∣) holds (ℓp sums of atoms converge in S′ and in Hp with p=1).

Proof

technique · direct
1.1F1

By [F1] fix ℓ1-coefficients (λj) and atoms (aj), indexing both sequences by j≥1, with f=∑jλjaj converging in S′ and with ∑j∣λj∣≤C∥f∥H1; by the same item the partial sums SN:=∑1≤j≤Nλjaj converge to f in the H1 norm.

2.1step 1.1F2

Since ∥f−SN∥H1→0 as N→∞ by step 1.1 and ε>0, there is N≥1 with ∥f−SN∥H1<ε; the sum SN is a finite linear combination of the atoms a1,…,aN with coefficients λ1,…,λN, and [F2] gives the same conclusion with the explicit tail bound.

3.1step 2.1∎

Thus for every f∈H1(Rn) and every ε>0 there is a finite atomic sum within ε in the H1 norm, which is density. Countable Choice is inherited from the atomic characterisation.

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