Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Distinct local full-defect blocks induce to distinct global blocks

Statement

Fix DG and N=NG(D). If blocks b,c of kN have defect group D and bG=cG, then b=c. No choice assumption is needed.

Facts & Assumptions

Given: The stated blocks and common induced block B.

[F1]

Every local full-defect block induces to a global block of defect D proves bG is defined and has defect group D.

[F2]

A global block of defect D determines a local block of defect D proves a global defect-D block has exactly one local inducing block.

[F3]

Centralizer containment makes block induction well-defined gives the local-to-global central-character criterion.

[F4]

Modular block central characters correspond to blocks identifies a local block by its value one on its primitive idempotent.

Proof

1.1

F1 applies to b and gives that the common block B has defect group D. Therefore F2 applies to this actual global block and subgroup, giving one primitive local idempotent e=BrD(f), where f is the idempotent of B.

F1F2algebra
2.1

Both induced characters take value one at f. By F3, λb(e)=λc(e)=1. Since e is primitive by step 1.1, F4 forces both local blocks to be kNe. Hence b=c. This proves injectivity even if the set of such blocks has zero or one element. For D=1 or N=G it is the identity case of F2. Only finite idempotent identifications occur; no claim about the vertex of an arbitrary restriction summand is used.

F2F3F4step 1.1algebra

Depends on

Used by

Dependency tree · two levels

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Sources